Answer:
120°; 240°
Step-by-step explanation:
Let's first solve for 
: 
At this point it's just a matter of drawing a circle, and mark where the angle is(please excuse my paint skills, but free hand drawing would be even worse). Red line, is 
on the cosines, and both the green and blue lines are valid solutions. The green line is a quarter of a circle, plus 30°, or 120°. The blue one is 3/4 of a circle, minus 30 degrees, or 240°.
What the question? Tell me then I can maybe help
To solve for the area of a triangle, we multiply the length and height, then divide that by two. L = 10. H = 7.
To solve for the perimeter, or edges, of the triangle, we need to use the Pythagorean Theorem: a² + b² = c² to solve for the third side. We already know two measures: 10 and 7. Now we need to square them, add them together to get c², then take the root of that number.
We cannot simplify √149, so we either leave it, or round it.
This is rounded to the nearest 10,000.
Now that we have the measure of the longest side, we can add all three sides together to get the perimeter of the triangle.
The statement says, "Triangle ABC has vertices A(1,2), B(1,5), and C(4,2) and undergoes a transformation."
The question asked is to find the set of vertices that does not belong to the group. This means that an attachment is expected to be there. The absence of any attachment makes this question hard to answer. Maybe this helps answer you question.
