Solve please, I don’t need work just an answer please
2 answers:
You might be interested in
let's keep in mind that, in the II Quadrant, cosine is negative and sine, is positive.
cosine is adjacent/hypotenuse, however the hypotenuse is simply a radius unit, and thus is never negative, so in the -(2/3) the negative must be the numerator, -2.
Answer:
The values of a and b are:
- a = 2
- b = 2
Step-by-step explanation:
We know that the slope-intercept form of the line equation
y = ax+b
where
- a is the slope
- b is the y-intercept
From the diagram of the line graph, we can fetch the two points
- (0, 2)
- (-1, 0)
Determining the slope between (0, 2) and (-1, 0)
Thus, the value of a = 2
We know that the value of the y-intercept can be determined by setting x = 0, and determining the corresponding value of y.
From the graph, it is clear
at x = 0, y = 2
Thus, the y-intercept b = 2
now substituting a = 2 and b = 2 in the slope-intercept form of the line equation
y = ax+b
y = 2x + 2 ∵ a = 2 , b = 2
Thus, the line of equation is:
y = 2x+2
now comparing with y = ax+b
Here:
a = 2
b = 2
Therefore, the values of a and b are:
- a = 2
- b = 2