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Strike441 [17]
4 years ago
13

The effect of chlorofluorocarbons (such as CCl2F2(g)) on the depletion of the ozone layer is well known. The use of substitutes,

such as CH3CH2F(g), for the chlorofluorocarbons, has largely corrected the problem. Calculate the volume (in L) occupied by 14.6 g of each of these compounds at STP. (a) CCl2F2(g) L (b) CH3CH2F(g) L
Chemistry
1 answer:
Alex4 years ago
7 0

Explanation:

a) Pressure of the gas a STP = P = 1 atm

Temperature f the gas at STP = T = 273.15 K

Moles of given gas i.e. CCl_2F_2 at STP = n

n=\frac{14.6 g}{121 g/mol}=0.1207 mol

Volume occupied by the given gas = V

PV=nRT  (ideal gas equation)

V=\frac{nRT}{P}=\frac{0.1207 mol\times 0.0821 atm l/mol K\times 273.15 K}{1 atm}=2.71 L

The volume occupied by 14.6 grams of CF_2Cl_2 is 2.71 liters.

b) Pressure of the gas a STP = P = 1 atm

Temperature f the gas at STP = T = 273.15 K

Moles of given gas i.e. CH_3CH_2F at STP = n

n=\frac{14.6 g}{48g/mol}=0.3042 mol

Volume occupied by the given gas = V

PV=nRT

V=\frac{nRT}{P}=\frac{0.3042mol\times 0.0821 atm l/mol K\times 273.15 K}{1 atm}=6.82 L

The volume occupied by 14.6 grams of CH_3CH_2F is 6.82 liters.

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what is the molarity of a solution prepared dissolving 317 g of CaCl2 into enough water to make 2.50 L of solution?
Minchanka [31]

Answer:

1.14 M

Explanation:

Step 1: Calculate the moles corresponding to 317 g of calcium chloride (solute)

The molar mass of calcium chloride is 110.98 g/mol.

317 g CaCl₂ × 1 mol CaCl₂/110.98 g CaCl₂ = 2.86 mol CaCl₂

Step 2: Calculate the molarity of the solution

Molarity is equal to the moles of solute divided by the liters of solution.

M = moles of solute / liters of solution

M = 2.86 mol / 2.50 L = 1.14 mol/L = 1.14 M

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A rigid 3.80 L sealed vessel contains 0.650 mol Ne, 0.321 mol Kr, and 0.190 mol Xe. Find the density of the mixture in g/L.
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Answer:

17.09g/L

Explanation:

Density = total mass of elements/ volume

We need to find the mass of each mixture constituents using their molar mass:

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For Neon (Ne) which contains 0.650mol;

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Density = total mass / volume

Density = 64.96g / 3.80L

Density of the mixture = 17.09g/L

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