<u><em>Ponds and rivers are two types of . . . . freshwater ecosystems</em></u>
Answer:
C.0.28 V
Explanation:
Using the standard cell potential we can find the standard cell potential for a voltaic cell as follows:
The most positive potential is the potential that will be more easily reduced. The other reaction will be the oxidized one. That means for the reactions:
Cu²⁺ + 2e⁻ → Cu E° = 0.52V
Ag⁺ + 1e⁻ → Ag E° = 0.80V
As the Cu will be oxidized:
Cu → Cu²⁺ + 2e⁻
The cell potential is:
E°Cell = E°cathode(reduced) - E°cathode(oxidized)
E°cell = 0.80V - (0.52V)
E°cell = 1.32V
Right answer is:
<h3>C.0.28 V
</h3>
<h3 />
Answer:
6
Explanation:
Li has an oxydation number of 1 2*1 = 2
O has an oxidation number of -2 4(-2) = -8
S has an oxydation number of x 1 * x = x
The oxidation number on the molecule is 0.
So here is the equation
2 - 8 + x = 0 Combine like terms
-6 + x = 0 Add 6 to both sides
-6 + 6 + x = 6 Combine like terms
x = 6
Sulphur in this case has an oxidation number of 6
A result of the common ion effect is that the selective precipitation of a metal ion, such as Ag+, is promoted by the addition of an appropriate counter ion (X-) that produces a compound (AgX) with a very low solubility.
Answer:
▄▄▄▀▀▀▄▄███▄
░░░░░▄▀▀░░░░░░░▐░▀██▌
░░░▄▀░░░░▄▄███░▌▀▀░▀█
░░▄█░░▄▀▀▒▒▒▒▒▄▐░░░░█▌
░▐█▀▄▀▄▄▄▄▀▀▀▀▌░░░░░▐█▄
░▌▄▄▀▀░░░░░░░░▌░░░░▄███████▄
░░░░░░░░░░░░░▐░░░░▐███████████▄
░░░░░le░░░░░░░▐░░░░▐█████████████▄
░░░░toucan░░░░░░▀▄░░░▐██████████████▄
░░░░░░has░░░░░░░░▀▄▄████████████████▄
░░░░░arrived░░░░░░░░░░░░█▀██████
Explanation: