Answer:
6
Explanation:
Li has an oxydation number of 1 2*1 = 2
O has an oxidation number of -2 4(-2) = -8
S has an oxydation number of x 1 * x = x
The oxidation number on the molecule is 0.
So here is the equation
2 - 8 + x = 0 Combine like terms
-6 + x = 0 Add 6 to both sides
-6 + 6 + x = 6 Combine like terms
x = 6
Sulphur in this case has an oxidation number of 6
