First One is the bottom one on the first column.
Second one is the top one on the first column.
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Confused what the question is. Are you looking for the product or the zeroes?
If you are looking for the product, then:
Use foil to get: sec²(1) - sec²(-csc²) -1(1) -1(-csc²)
= sec² + sec²csc² - 1 + csc²
= sec²csc² + sec² + csc² - 1
= sec²csc² + 1 - 1 (NOTE: sec² + csc² = 1 is an identity)
= sec²csc²
Answer: sec²csc²
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If you are looking for the zeroes, then:
Using the zero product property, set each factor equal to zero and solve.
<u>First factor:</u>
sec²Θ - 1 = 0
sec²Θ = 1
secΘ = 1, -1
remember that secΘ is 
= 1
= -1
cross multiply to get:
cosΘ = 1 cosΘ = -1
use the unit circle (or a calculator) to find that Θ = 0 and π
<u>Second factor:</u>
1 - csc²Θ = 0
1 = csc²Θ
1, -1 = cscΘ
remember that cscΘ is 
= 1
= -1
cross multiply to get:
sinΘ = 1 sinΘ = -1
use the unit circle (or a calculator) to find that Θ =
and
Answer: 0, π,
,
Answer:
For <em>2</em>, 30 cubic m., For <em>3</em>, 90 cubic cm., For <em>4</em>, 1000 cubic yards, for <em>5</em>, 27 cubic mm., For <em>6</em>, 120 cubic in.
Step-by-step explanation:
You can simply multiply all 3 sides to get the cubic volume B x <em>h </em>is the same as<em> l</em> x <em>w </em>x <em>h</em>
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<em>ex. </em>Number 2, length 3, width 2, height 5
Base is<em> 2x3=6 </em>times <em>5 = 30 </em>or<em> 2 x 3 x 5=30</em>
Answer:
Hey there!





Let me know if this helps :)
Answer:
Step-by-step explanation:
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