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Arada [10]
4 years ago
5

Nellie charges $4.25 for the first hour she baby-sits and $2.75 for each additional hour or part of an hour. How much will she e

arn for baby-sitting from 7:15 P.M. until 1:30 A.M.?
Mathematics
1 answer:
Brilliant_brown [7]4 years ago
8 0

Answer:

ok so from 7:15 to 8:15 it cost 4.25

8:15 to 9:15 = 2.75

9:15 to 10:15 = 2.75

10:15 to 11:15 = 2.75

11:15 to 12:15 = 2.75

12:15 to 1:15 = 2.75

1:15 to 1:30 = 1.37

so add 4.25+2.75+2.75+2.75+2.75+2.75+1.37

which equals 19.37

<u>Nellie will earn $19.37 for baby-sitting from 7:15 PM until 1:30 AM</u>

step-by-step explanation:

hope this helps plz mark me as brainiest

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If X and Y are independent continuous positive random
Leni [432]

a) Z=\frac XY has CDF

F_Z(z)=P(Z\le z)=P(X\le Yz)=\displaystyle\int_{\mathrm{supp}(Y)}P(X\le yz\mid Y=y)P(Y=y)\,\mathrm dy

F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}P(X\le yz)P(Y=y)\,\mathrm dy

where the last equality follows from independence of X,Y. In terms of the distribution and density functions of X,Y, this is

F_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy

Then the density is obtained by differentiating with respect to z,

f_Z(z)=\displaystyle\frac{\mathrm d}{\mathrm dz}\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy=\int_{\mathrm{supp}(Y)}yf_X(yz)f_Y(y)\,\mathrm dy

b) Z=XY can be computed in the same way; it has CDF

F_Z(z)=P\left(X\le\dfrac zY\right)=\displaystyle\int_{\mathrm{supp}(Y)}P\left(X\le\frac zy\right)P(Y=y)\,\mathrm dy

F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}F_X\left(\frac zy\right)f_Y(y)\,\mathrm dy

Differentiating gives the associated PDF,

f_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}\frac1yf_X\left(\frac zy\right)f_Y(y)\,\mathrm dy

Assuming X\sim\mathrm{Exp}(\lambda_x) and Y\sim\mathrm{Exp}(\lambda_y), we have

f_{Z=\frac XY}(z)=\displaystyle\int_0^\infty y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy

\implies f_{Z=\frac XY}(z)=\begin{cases}\frac{\lambda_x\lambda_y}{(\lambda_xz+\lambda_y)^2}&\text{for }z\ge0\\0&\text{otherwise}\end{cases}

and

f_{Z=XY}(z)=\displaystyle\int_0^\infty\frac1y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy

\implies f_{Z=XY}(z)=\lambda_x\lambda_y\displaystyle\int_0^\infty\frac{e^{-\lambda_x\frac zy-\lambda_yy}}y\,\mathrm dy

I wouldn't worry about evaluating this integral any further unless you know about the Bessel functions.

6 0
3 years ago
A major department store chain is interested in estimating the mean amount its credit card customers spent on their first visit
sergiy2304 [10]

Answer:

95% Confidence interval: (39.43, 61.58)

Step-by-step explanation:

We are given the following in the question:

Sample mean, \bar{x} = $50.50

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation = 20

95% Confidence interval:

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 14 and}~\alpha_{0.05} = \pm 2.1447  

=50.50 \pm 2.1447(\dfrac{20}{\sqrt{15}} ) \\\\= 50.50 \pm 11.0751 \\= (39.4249,61.5751)\\\approx (39.43, 61.58)  

95% Confidence interval: (39.43, 61.58)

8 0
3 years ago
#4- A baby weighed 7.6 pounds at birth and 9 1/2 pounds after 6 Weeks. What was the percent increase?
ivanzaharov [21]
The pounds increased 1.6 hope this helped
3 0
3 years ago
The Holcombe family went out to dinner
Jet001 [13]

Answer:

$13.77 per person in the family

Step-by-step explanation:

Cost of the meal = $54.65

Sales tax rate = 8%

Sales tax amount = 8% of $54.65

= 8/100 × 54.65

= 0.08 × 54.65

= $4.372

Tip = 18% of $54.65

= 18/100 × 54.65

= 0.18 × 54.65

= $9.837

Total cost of the dinner = Cost of the meal + Sales tax amount + Tip

= $54.65 + $4.372 + $9.837

= $68.859

There are 5 people in the Holcombe family

What was the cost per person for the meal, including sales tax and tip?

cost per person for the meal, including sales tax and tip = Total cost of the dinner / total number of people in the family

= $68.859 / 5

= $13.7718

Approximately

$13.77 per person in the family

5 0
3 years ago
Please help me solve this
alexandr1967 [171]

Answer:

20.5

Step-by-step explanation:

By the Triangle Midsegment Theorem, the midsegment connecting the midpoints of two sides of a triangle is parallel to the third side of the triangle, and the length of this midsegment is half the length of the third side. Therefore, (1/2)FH ≡ IH, (1/2)HG ≡ HJ. Knowing that IJ = 8 gives you the presidence to solve for the perimeter.

3 0
3 years ago
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