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Helga [31]
3 years ago
14

Is 42 a multiple of 7

Mathematics
2 answers:
guajiro [1.7K]3 years ago
6 0
Yes 42 is a multitude of 7
7x6 is 42
aev [14]3 years ago
5 0

Answer:

yes

Step-by-step explanation:

7 * 6 = 42

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Delvig [45]

Answer:

1045384620173418506891046 number of copies

Step-by-step explanation:

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4 years ago
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CAN SOMEONE WHO KNOWS HOW TO DO THIS PLEASE HELP ME
7nadin3 [17]
Firstly start off with finding the lowest common multiple of 14 and 24. The LCM would be 168. Then you would look at your powers, here you have to choose the highest power of each letter. So 14x^4 and 24x^6 the highest is x^6, then for y it would be y^6 and then for z it would be z^8. So altogether your answer would be 168x^6y^6z^8
4 0
3 years ago
WILL GIVE BRAINLIEST& 15 PTS.
kicyunya [14]

Answer:

The given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

Step-by-step explanation:

Consider the given fraction \frac{x^3-x^2}{x^3}

We have to reduce the fraction to the lowest terms.

Consider numerator x^3-x^2

We can take x² common from both the term,

Thus, numerator can be written as x^2(x-1)

Given expression can be rewritten as ,

\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}

We can now cancel x^2 from both numerator and denominator,

\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}

\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}

Thus, the given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

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3 years ago
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So you can you the Pythagorean theorem to solve this problem.

if each side of the square is a certain length x, then the square is made up of two right triangles.

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a^2 + b^2 = c^2

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2x^2 = 1296

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x = 25.456

area of a square = x^2 = 648 ft^2
3 0
3 years ago
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