There's a 1 in 10 chance that you get the first place correct. Next, since there are 9 horses left to choose from since the same person or something can't be first and second , there's a 1 in 9 chance for second place and 1/8 for third using that logic. Multiplying them all together, we get a 1/720 chance of guessing all three right
Answer:
58
Step-by-step explanation:
Let t and m represent the numbers of cards had by Tom and Max, respectively. Then the problem statement tells us ...
We want to solve for t. If we multiply the first equation by 4 and subtract the second, we get ...
... 4(t +m) -(4m +2) = 4(72) -(t)
... 4t +4m -4m -2 = 288 -t . . . . . . . eliminate parentheses
... 5t = 290 . . . . . . . . . . . . . . . . . . . add t+2, collect terms
... t = 58 . . . . . . . . divide by the coefficient of t
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<em>Alternate Solution</em>
You can work this in your head if you realize that subtacting 2 from the total means that Max has 1/5 of the new amount. 1/5 of 70 is 14, so Tom has 72 - 14 = 58 cards.
Answer:
A
Step-by-step explanation:
Answer:
A) 0.5
B) 0.375
C) 0.375
D) 0.167
Step-by-step explanation:
Let's call
a: Ariel
b: Bob
c: Chris
d: Diana
There are 4*3*2*1 = 24 total combinations to order the 4 children
A) Ariel is older than Diana in the following 12 cases:
a b c d
a b d c
a c b d
a c d b
a d b c
a d c b
b a c d
b a d c
b c a d
c a b d
c a d b
c b a d
Then, the probability is 12/24 = 0.5
B) The condition "Ariel is older than Diana, if it is given that Ariel is older than Bob" is satisfied in the six first cases and last three cases of before.
Then, the probability is 9/24 = 0.375
C) Ariel is older than Diana, if it is given that Chris is older than Diana, in the following cases:
a b c d
a c b d
a c d b
a d c b
b a c d
b c a d
c a b d
c a d b
c b a d
Then, the probability is 9/24 = 0.375
D) Ariel is older than Diana, if it is given that Diana is older than Bob, in the following cases:
a c d b
a d b c
a d c b
c a d b
Then, the probability is 4/24 = 0.167
Answer:
Step-by-step explanation:
The equation is x^4 – 5x^2 – 36 = 0
We will break the middle term:
Firstly multiply the coefficient of x^4 by constant term of the equation:
1*36 = 36
Now find any two numbers whose product is 36 and their sum or difference is equal to 5
9*4 = 36
9-4 = 5
Now,
x^4 – 5x^2 – 36 = 0
x^4-9x^2+4x^2-36=0
Now take the common:
x^2(x^2-9)+4(x^2-9)=0
(x^2+4)(x^2-9)=0
x²+4=0,
x²= 0-4,
x²=-4,
Take root on both sides:
√x²=+/-√-4
+/-√-4 = +/-√-1 *√4
√-1 = i
Then +/-√-1 *√4 = √4 i
We know that the root of 4 is 2
Then we can write it as +/-2i
Thus x = 2i , -2i
Now (x^2-9)= 0
x²=0+9
x²=9
Take square root on both sides:
√x²=√9
x=+/-3
x= 3, -3
Therefore the values of x are 2i, -2i, 3 , -3 ....
