What z score in a normal distribution has 33% of all score above it?
Answer: A z score which has 33% of all scores above it, will have 67% of all scores below it.
To find the required z score, we need to find the z value corresponding to probability 0.67.
Using the standard normal table, we have:
Therefore, the z score = 0.44 has 33% of all score above it.
The cube root of 3 is 1.44224957031
Coefficient of 'x'= 5a
Coefficient of 'x square'= -17
Constant term = 14a
Answer:
-x + -13
Step-by-step explanation:
Rewrite: 5(x – 4) + 3x – 9x + 7
Step 1: 5(x + –4) + 3x + –9x + 7
Step 2: 5x + -20 + 3x + –9x + 7
Step 3: 5x + 3x + –9x + -20 + 7
Step 4: -1x + -13
Step 5: -x + -13
Answer:
hope this helps
Step-by-step explanation:
solution:
x^2 + 3x + 5 = x + 13
x^2 + 2x -8 = 0
(x+4)(x-2) = 0
x = -4 or x = 2
if x = -4, y = 9
if x = 2 , y = 15
