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salantis [7]
4 years ago
8

Which statement correctly identifies a local minimum of the graphed function? Over the interval [–3, –2], the local minimum is 0

. Over the interval [–2, –1], the local minimum is 2.2. Over the interval [–1, 0.5], the local minimum is 1. Over the interval [0.5, 2], the local minimum is 4.
Mathematics
1 answer:
marta [7]4 years ago
4 0

Answer:

C.

Step-by-step explanation:

As we can see on the graph C is our answer.

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6 ( 7y - 5) simplified
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Step-by-step explanation:

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3 years ago
(1) a) 5270 cl= ? dal
Ivanshal [37]

Answer:

Check below

Step-by-step explanation:

1) These metric volume units can be easily converted by dividing or multiplying by 10 and its multiple. Like this: each step up on the ladder multiply by 10. Each step down divide by 10

a)5270 \:cl=527\:dl\\b)kl=5.3 \times 10=530 hl\\c)58000ml=5.8 dal =(\frac{58000}{10000})\\d)0.39 dal=3.9 l\\e)7.8 dal=780 dl\\f)57.2 ml=5.72 cl.

2) When it comes to area, the "ladder scheme" remains valid but now we'll multiply or divide by

10^3

Bear in mind these useful relations:

1litre =\frac{1}{10^3}m^{3}

1 cm^{3} =1 ml

a) 3.7 l=3700 cm^{3}\\b)29.6 dm^{3}\\29.6 dm^{3} \rightarrow 29.6\times10^{3} cm^3=29.6\times10^{3} ml = 29.6\times10^{2} cl \:or\:2960 cl\\c)8.1l=8100 cm^{3}\\d)5l=\frac{5}{10^{-3}} m^{3}\\e)5.2 cl=52ml=52 cm^{3}=52\times10^{3}=52000 \:mm^{3}\\f)375 ml=375 cm^{3}\\g) 1300 cm^{3}=1300 ml=13 dl\\h) 8.6 ml= 8.6 cm^{3}\times\: 10^{3}=8600 mm^{3}\\i) 51.8\times 10^{11} l \rightarrow 51.8\times 10^{-11}km^{3}

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3 years ago
Tom makes 145.80 in 3 days. How much does he make in 2 days
ArbitrLikvidat [17]
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6 0
3 years ago
Which statement about the function f(x)=|x+3| is true?
Stels [109]

The given function f(x) = |x + 3| has both an absolute maximum and an absolute minimum.

What do you mean by absolute maximum and minimum ?

A function has largest possible value at an absolute maximum point, whereas its lowest possible value can be found at an absolute minimum point.

It is given that function is f(x) = |x + 3|.

We know that to check if function is absolute minimum or absolute maximum by putting the value of modulus either equal to zero or equal to or less than zero and simplify.

So , if we put |x + 3| = 0 , then :

± x + 3 = 0

±x = -3

So , we can have two values of x which are either -3 or 3.

The value 3 will be absolute maximum and -3 will be absolute minimum.

Therefore , the given function f(x) = |x + 3| has both an absolute maximum and an absolute minimum.

Learn more about absolute maximum and minimum here :

brainly.com/question/17438358

#SPJ1

5 0
1 year ago
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