Answer:
I believe it would be the last table.
Step-by-step explanation:
A linear function has an equation of y=Mx+b where y and x are the variables but m (the slope) and b are constants. The slope for the last table is -8 as the y values are decreasing by 8 every time you move forward one in the x axis. None of the other tables have a constant slope which means they don’t have straight lines when you graph them. Therefore, the last table would have to be the only one representing a linear function
Answer: g = 42
Step-by-step explanation:
g/3 + 11 = 25
First, subtract 11 to both sides
g/3 = 14
Then, multiply 3 to both sides to get rid of the fraction
g=42
Answer: The sphere is 0.002548 cm travel up the plane.
Step-by-step explanation:
Since we have given that
Inclination angle = 30°
Translational speed = 0.25 m/s
As we know that

and
Length of solid sphere is given by

So, it becomes,

And 
So, it becomes,

Hence, the sphere is 0.002548 cm travel up the plane.
Answer:
1.7689 (rounded to 4 decimal places)
Step-by-step explanation:
Let the number we are seeking be "x", thus we can write the equation as:

Since we have raised "x" to the "10th power", to get "x" back again, we need to take 10th root. Same goes for right side, we take 10th root of 300. We will get our answer. The process shown below:
![x^{10}=300\\\sqrt[10]{x^{10}} =\sqrt[10]{300} \\x=\sqrt[10]{300} \\x=1.7689](https://tex.z-dn.net/?f=x%5E%7B10%7D%3D300%5C%5C%5Csqrt%5B10%5D%7Bx%5E%7B10%7D%7D%20%3D%5Csqrt%5B10%5D%7B300%7D%20%5C%5Cx%3D%5Csqrt%5B10%5D%7B300%7D%20%5C%5Cx%3D1.7689)
hence, 1.7689 raised to 10th power will give us 300
Answer:
Explained below.
Step-by-step explanation:
Convenience sampling is a kind of non-probability-sampling (i.e. all items doesn’t have an equivalent chance of being selected), which doesn’t comprises of random collection of items.
Convenience sampling is where we take in items which are easy to reach. This sort of sampling technique results in a biased sample.
Systematic sampling is a kind of probability sampling method in which individuals from a larger population are nominated according to a random initial point and a static, periodic interval. If the individual <em>k</em> is selected as the first sample then the sample space consists of every <em>k</em>th individual.
In this case the first sample is an example of convenience sample and the second is a systematic sample.