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5x + 3y = - 53
the equation of a line in ' slope- intercept form ' is y = mx + c
where m is the slope and c the y-intercept
rearrange 3x - 5y = - 15 into this form to obtain m → (subtract 3x from both sides)
- 5y = - 3x - 15 → divide all terms by - 5 )
y = x + 3 → in slope-intercept form with m =
given a line with slope m then the slope m₁ of a line perpendicular to it is
m₁ = - = - 1 ÷
= -
partial equation is y = - x + c
to find c substitute ( - 7, - 6) into the partial equation
- 6 = + c ⇒ c = - 6 -
= -
y = - x -
→ in slope intercept form
multiply all terms by 3
3y = - 5x - 53 → ( add 5x to both sides )
5x + 3y = - 53 → in standard form
Answer and explanation:
To find : Calculate to the nearest 1/10th meter the length of the side of a 7th, 12th, and 30th hectare square plot.
Solution :
The area of the square is given by,
where s is the side length.
We know,
1) The area of square plot is 7 hectare.
Area in meter square is
Substitute the value in the formula,
Side nearest to 1/10th meter is 264.8 meter.
2) The area of square plot is 12 hectare.
Area in meter square is
Substitute the value in the formula,
Side nearest to 1/10th meter is 346.4 meter.
3) The area of square plot is 30 hectare.
Area in meter square is
Substitute the value in the formula,
Side nearest to 1/10th meter is 547.7 meter.