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3 years ago

8

What is 2 ( c + 1) - 6 = 8

1 answer:

Elodia [21]3 years ago

3 0

Answer:

x = 6

Whole equation: 2 ( 6 + 1 ) - 6 = 8

Step-by-step explanation:

2 ( c + 1 ) - 6 = 8

2c + 2 - 6 = 8

2c - 4 = 8

<u> +4 +4 </u>

<u>2c</u> = <u>12</u>

2 2

c = 6

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3 years ago

Please someone help me...

laiz [17]

Step-by-step explanation:

First factor out the negative sign from the expression and reorder the terms

That's

$\frac{1}{ - (( \tan(2A) - \tan(6A) )} - \frac{1}{ \cot(6A) - \cot(2A) }$

<u>Using trigonometric </u><u>identities</u>

That's

<h3> $\cot(x) = \frac{1}{ \tan(x) }$ </h3>

<u>Rewrite the expression</u>

That's

$\frac{1}{ - (( \tan(2A) - \tan(6A) )} - \frac{1}{ \frac{1}{ \tan(6A) } } - \frac{1}{ \frac{1}{ \tan(2A) } }$

We have

<h3> $- \frac{1}{ \tan(2A) - \tan(6A) } - \frac{1}{ \frac{ \tan(2A) - \tan(6A) }{ \tan(6A) \tan(2A) } }$ </h3>

<u>Rewrite the second fraction</u>

That's

<h3> $- \frac{1}{ \tan(2A) - \tan(6A) } - \frac{ \tan(6A) \tan(2A) }{ \tan(2A) - \tan(6A) }$ </h3>

Since they have the same denominator we can write the fraction as

$- \frac{1 + \tan(6A) \tan(2A) }{ \tan(2A) - \tan(6A) }$

Using the identity

<h3> $\frac{x}{y} = \frac{1}{ \frac{y}{x} }$ </h3>

<u>Rewrite the expression</u>

We have

<h3> $- \frac{1}{ \frac{ \tan(2A) - \tan(6A) }{1 + \tan(6A) \tan(2A) } }$ </h3>

<u>Using the trigonometric identity</u>

<h3> $\frac{ \tan(x) - \tan(y) }{1 + \tan(x) \tan(y) } = \tan(x - y)$ </h3>

<u>Rewrite the expression</u>

That's

<h3> $- \frac{1}{ \tan(2A -6A) }$ </h3>

Which is

<h3> $- \frac{1}{ \tan( - 4A) }$ </h3>

<u>Using the trigonometric identity</u>

<h3> $\frac{1}{ \tan(x) } = \cot(x)$ </h3>

Rewrite the expression

That's

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<u>Simplify the expression using symmetry of trigonometric functions</u>

That's

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<u>Remove the parenthesis </u>

We have the final answer as

<h2> $\cot(4A)$ </h2>

As proven

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<em>_____________________________
Rewrite 13113 as 9 . 1457

Rewrite 1665 as 9 . 185
= 9 . 1457x + 9 . 185
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</em>

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