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Karolina [17]
4 years ago
7

Radius of 0.75 centimeters is rational or irrational

Mathematics
1 answer:
ella [17]4 years ago
6 0
A radius of 0.75 would be rational because the decimal ends and does not repeat itself.
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M/n = p/q solve for p
mojhsa [17]

Answer:

p=\frac{Mq}{n}

Step-by-step explanation:

we have

\frac{M}{n}=\frac{p}{q}

Solve for p

That means ----> Isolate the variable p

Multiply by q both sides

\frac{M}{n}(q)=\frac{p}{q}(q)

Simplify right side

\frac{M}{n}(q)=p

Rewrite

p=\frac{Mq}{n}

6 0
3 years ago
Find the area of the parallelogram.<br> 8 m<br> 2 m
nasty-shy [4]
If 2m and 8m are the base and height of the parallelogram, then the area is 16.
7 0
3 years ago
Need help finding slop please!
Soloha48 [4]
The slope is
1. Find ordered pairs ( 1 , -4 ) ( 3, 3)
The formula is
M= y2 - y1
_____
X2- X1
2. Replace the numbers
M = 3 - 4.
———
1-3
Subtract
3. You get -1/-2
4. Divide you get 0.5
( but if you need rise and run use -1/-2) rise top run bottom
Slope is 0.5 I think
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7 0
3 years ago
Which angles of the triangles measure 90°?
xxMikexx [17]

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6 0
3 years ago
Read 2 more answers
The​ life, in​ years, of a certain type of electrical switch has an exponential distribution with an average life β=44. If 100 o
Bond [772]

Answer:

0.9999

Step-by-step explanation:

Let X be the random variable that measures the time that a switch will survive.

If X has an exponential distribution with an average life β=44, then the probability that a switch will survive less than n years is given by

\bf P(X

So, the probability that a switch fails in the first year is

\bf P(X

Now we have 100 of these switches installed in different systems, and let Y be the random variable that measures the the probability that exactly k switches will fail in the first year.

Y can be modeled with a binomial distribution where the probability of “success” (failure of a switch) equals 0.0225 and  

\bf P(Y=k)=\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}

where  

\bf \binom{100}{k} equals combinations of 100 taken k at a time.

The probability that at most 15 fail during the first year is

\bf \sum_{k=0}^{15}\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}=0.9999

3 0
3 years ago
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