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Dmitrij [34]
4 years ago
7

How to factor (9x^2-3x-2)(x^2-6)

Mathematics
1 answer:
Ilia_Sergeevich [38]4 years ago
7 0

(9x^2-3x-2)(x^2-6)=(9x^2-6x+3x-2)(x^2-(\sqrt6)^2)\\\\=[3x(3x-2)+1(3x-2)](x-\sqrt6)(x+\sqrt6)\\\\=(3x-2)(3x+1)(x-\sqrt6)(x+\sqrt6)\\\\Used:\ a^2-b^2=(a-b)(a+b)

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