Which value of x would make the equation 3(2") = 9 true?

ivanzaharov [21]

Answer: 18w^2 - 6w + 4

Explanation:

(4 + 7w^2) - (6w - 11w^2)
= 4 + 7w^2 - 6w + 11w^2
= 18w^2 - 6w + 4

5 0

3 years ago

Paul has a stock portfolio worth $21,000. His home is valued at $365,000. His car is valued at $19,000. He owes $362,000 on his

kompoz [17]

Answer:

Paul has negative worth of $2,900

His statement is invalid as he did not consider all assets and debts in aggregate.

Step-by-step explanation:

The net worth of Paul is the total asset owned by him less the total of debts owed by him.

Paul's total assets can computed thus:

Stock portfolio $21,000

Home worth $365,000

Car worth $19,000

Total assets $405,000

Paul's total debts can be computed as follows:

Mortgage loan $362,000

Car loan $16,250

credit card debt $11,750

Student loan $17,900

Total debts $407,900

The amount of debts owed by Paul is $2,900($405,000-$407,900) more than his asset worth,which implies that Paul is indebted to the tune of $2,900,hence has negative worth.

6 0

3 years ago

What is the equation of the line that passes through the point (4, 12) and has a y-intercept of -2?

natima [27]

Answer:

The answer is D.

Step-by-step explanation:

:DDDDDDDDD

4 0

3 years ago

How many ways can the letters in the word balloon be arranged? 210 1,260 2,520 5,040

Lapatulllka [165]

Answer:

The number of ways this can be done is 1,260 ways

Step-by-step explanation:

In this question, we are asked to calculate the number of ways in which the letters of the word balloon can be arranged.

To do this, we take into consideration those letters that are repeated and the number of times repeated. The letters are l and o and are repeated two times each.

The number of ways = 7!/2!2! = 5040/4 = 1,260 ways

6 0

4 years ago

A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature

Westkost [7]

Answer:

(a) The value of k is $\frac{1}{15}$ .

(b) The probability that at most three forms are required is 0.40.

(c) The probability that between two and four forms (inclusive) are required is 0.60.

(d) $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ is not the pmf of y.

Step-by-step explanation:

The random variable Y is defined as the number of forms required of the next applicant.

The probability mass function is defined as:

$P(y) = \left \{ {{ky};\ for \ y=1,2,...5 \atop {0};\ otherwise} \right$

(a)

The sum of all probabilities of an event is 1.

Use this law to compute the value of k.

$\sum P(y) = 1\\k+2k+3k+4k+5k=1\\15k=1\\k=\frac{1}{15}$

Thus, the value of k is $\frac{1}{15}$ .

(b)

Compute the value of P (Y ≤ 3) as follows:

$P(Y\leq 3)=P(Y=1)+P(Y=2)+P(Y=3)\\=\frac{1}{15}+\frac{2}{15}+ \frac{3}{15}\\=\frac{1+2+3}{15}\\ =\frac{6}{15} \\=0.40$

Thus, the probability that at most three forms are required is 0.40.

(c)

Compute the value of P (2 ≤ Y ≤ 4) as follows:

$P(2\leq Y\leq 4)=P(Y=2)+P(Y=3)+P(Y=4)\\=\frac{2}{15}+\frac{3}{15}+\frac{4}{15}\\ =\frac{2+3+4}{15}\\ =\frac{9}{15} \\=0.60$

Thus, the probability that between two and four forms (inclusive) are required is 0.60.

(d)

Now, for $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ to be the pmf of Y it has to satisfy the conditions:

$P(y)=\frac{y^{2}}{50}>0;\ for\ all\ values\ of\ y \\$
$\sum P(y)=1$

Check condition 1:

$y=1:\ P(y)=\frac{y^{2}}{50}=\frac{1}{50}=0.02>0\\y=2:\ P(y)=\frac{y^{2}}{50}=\frac{4}{50}=0.08>0 \\y=3:\ P(y)=\frac{y^{2}}{50}=\frac{9}{50}=0.18>0\\y=4:\ P(y)=\frac{y^{2}}{50}=\frac{16}{50}=0.32>0 \\y=5:\ P(y)=\frac{y^{2}}{50}=\frac{25}{50}=0.50>0$

Condition 1 is fulfilled.

Check condition 2:

$\sum P(y)=0.02+0.08+0.18+0.32+0.50=1.1>1$

Condition 2 is not satisfied.

Thus, $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ is not the pmf of y.

7 0

3 years ago