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matrenka [14]
3 years ago
11

Which value of x would make the equation 3(2") = 9 true?

Mathematics
1 answer:
MArishka [77]3 years ago
5 0

Answer:

+1

Step-by-step explanation:

3(2+1)

3(3)

9

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Fourteen is 6 less a number (n). Which equation shows this relationship?
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Answer:

14+6=n=20

Step-by-step explanation:n=20

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The perimeter of a square is 56 cm. What is the approximate length of its diagonal? A.10.6 cm
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Derivative, by first principle<br><img src="https://tex.z-dn.net/?f=%20%5Ctan%28%20%5Csqrt%7Bx%20%7D%20%29%20" id="TexFormula1"
vampirchik [111]
\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}h

Employ a standard trick used in proving the chain rule:

\dfrac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\cdot\dfrac{\sqrt{x+h}-\sqrt x}h

The limit of a product is the product of limits, i.e. we can write

\displaystyle\left(\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\right)\cdot\left(\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt x}h\right)

The rightmost limit is an exercise in differentiating \sqrt x using the definition, which you probably already know is \dfrac1{2\sqrt x}.

For the leftmost limit, we make a substitution y=\sqrt x. Now, if we make a slight change to x by adding a small number h, this propagates a similar small change in y that we'll call h', so that we can set y+h'=\sqrt{x+h}. Then as h\to0, we see that it's also the case that h'\to0 (since we fix y=\sqrt x). So we can write the remaining limit as

\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan\sqrt x}{\sqrt{x+h}-\sqrt x}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{y+h'-y}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{h'}

which in turn is the derivative of \tan y, another limit you probably already know how to compute. We'd end up with \sec^2y, or \sec^2\sqrt x.

So we find that

\dfrac{\mathrm d\tan\sqrt x}{\mathrm dx}=\dfrac{\sec^2\sqrt x}{2\sqrt x}
7 0
3 years ago
I need help with the steps. The answer is (5,2)
Elden [556K]

So with this, I will be using the substitution method. With the first equation, substitute (y+3) into the x variable and solve for y:

y+3+y=7\\2y+3=7\\2y=4\\y=2

Next, now that we have the value of y, substitute it into either equation to solve for x:

x+2=7\\x=5\\\\x=2+3\\x=5

<u>And this is how you get your final answer (5,2).</u>

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3 years ago
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lara [203]

F=\{\ x\ |\ x

F ∪ H is defined as the set that consists of all elements belonging to either set F or set H (or both).

F ∩ H is defined as the set composed of all elements that belong to both F and H

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