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3 years ago

10

Ok ik that I do math for ppl a lot but if someone could plz just help me with theses math problems (if u say that u will help I’

ll put my questions in the comments) it’s algebra 1

1 answer:

hodyreva [135]3 years ago

7 0

I will help you with your problem

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It is in simplest form.

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3 years ago

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Nina and Luca were told to draw a net for the three-dimensional figure shown below. Which statement about the students' nets is

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it was a three-dimensional figure

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In a recent year, 27.4% of all registered doctors were female. If there were 44,700 female registered doctors that year, what wa

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Answer:

1,224,780

Step-by-step explanation:

44,700 × 27.4= 1,224,780

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3 years ago

8x^3+9x^7+5x^3+2+7x^7

posledela

Answer:

16x^7+13x^3+2

Step-by-step explanation:

8x^3+9x^7+5x^3+2+7x^7

Add 8x^3 and 5x^3 (don’t add the exponents together )

13x^3+9x^7+2+7x^7

Add 9x^7 and 7x^7

13x^3+16x^7+2

Then put them in order from biggest exponent to smallest

16x^7+13x^3+2

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2 years ago

The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding

melamori03 [73]

Answer:

We conclude that the mean wedding cost is less than $30,000 as advertised.

Step-by-step explanation:

We are given the following data set:(in thousands)

29100, 28500, 28800, 29400, 29800, 29800, 30100, 30600

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{236100}{8} = 29512.5$

Sum of squares of differences = 3408750

$S.D = \sqrt{\frac{3408750}{7}} = 697.82$

Population mean, μ = $30,000

Sample mean, $\bar{x}$ = $29512.5

Sample size, n = 8

Alpha, α = 0.05

Sample standard deviation, s = $ 697.82

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 30000\text{ dollars}\\H_A: \mu < 30000\text{ dollars}$ We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{29512.5 - 30000}{\frac{697.82}{\sqrt{8}} } = -1.975$

Now,

$t_{critical} \text{ at 0.05 level of significance, 7 degree of freedom } = -1.894$

Since,

$t_{stat} < t_{critical}$

We fail to accept the null hypothesis and reject it.

We conclude that the mean wedding cost is less than $30,000 as advertised.

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4 years ago