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Aneli [31]
2 years ago
6

HELP ME!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
NARA [144]2 years ago
8 0

Answer:

1632cm3

Step-by-step explanation:

Hope it will help

<h2><em><u>Brainliest please</u></em></h2>
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A pond 85 feet across; 1 inch = 4 feet
enot [183]
Well... all u have to do is 85 divided by 4 which equals 21.25..... unless there is another part of the question!!
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3 years ago
Find the side length of the equilateral triangle whose area is the square root of 3 cm2
Alla [95]

Here, Given

Area of Equilateral triangle = 3cm2

therefore, we know;

Area of Equilateral triangle =( \sqrt{3}÷4)×a^{2}

so,

3 =( \sqrt{3}÷4)×a^{2}

3÷( \sqrt{3}÷4) = a^{2}

2.63 cm = a .

The area of ​​an equilateral triangle is the area covered by an equilateral triangle on a two-dimensional plane. An equilateral triangle is a triangle with all sides equal and all angles at 60 degrees. The area of ​​the shape is the number of unit squares that fit inside.

Here, "unit" refers to 1, and a unit square is a square with one side. Alternatively, the area of ​​an equilateral triangle is the total amount of space it surrounds in a two-dimensional plane.

Learn more about Area of  triangle  here: brainly.com/question/17335144

#SPJ4

6 0
2 years ago
19. Using clay, a student made a right circular cone of height 48cm and base
aev [14]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
What is the simplest form of 54/54
krek1111 [17]
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4 0
3 years ago
Read 2 more answers
Given the diagram below. If G is the circumcenter of ABC. DC = 16, GB = 21 and AZ = 19, find each measure.​
Jlenok [28]

Answer:

Step-by-step explanation:

Properties of a circumcenter;

1). Circumcenter of a triangle is a point which is equidistant from all vertices.

2). Point where perpendicular bisectors of the sides of a triangle meet is called circumcenter of the triangle.

From the picture attached,

9). AG = GB = GC = 21

10). BC = 2(DC)

            = 2×16

            = 32

11). By applying Pythagoras Theorem in ΔGFB,

     GB² = GF² + FB²

     (21)² = GF² + (19)²

     441 = GF² + 361

     GF² = 441 - 361

     GF = \sqrt{80}

     GF = 8.9

12). By applying Pythagoras theorem in ΔGDB,

     GB² = DG² + BD²

     (21)² = (DG)² + (16)² [BD = DC = 16]

     DG² = 441 - 256

     DG = √185

     DG =  13.6

7 0
3 years ago
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