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Ivan
2 years ago
13

In reality, you would not serve multiple courses of soup at a meal. For this activity

English
1 answer:
Anastaziya [24]2 years ago
7 0

Ok, so for the appetizer you're going to want something light, it won't fill you up but it will still take the edge off of the hunger, I'd personally start with a wonton soup, or a sweet and sour soup. Then for the main course you are going to need something filling. Vegetable soup, or a chicken noodle soup. Dessert is going to be the hardest, especially since you'll have to make sure the textures and flavors are complementary. However, a desert doesn't always have to be 100 percent sweet. I would go with a sweet potato or a snow fungus soup for that

 

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The third sentence is correct on Sentence 2

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Click on number 3

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A “Cassandra” is someone who warns other people of a future danger but is not believed or heeded. The term comes from a story in
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B. To explain an origin of the term

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Five score years ago, a great American, in whose symbolic shadow we stand today, signed the Emancipation Proclamation. This mome
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Read the excerpts.
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2 years ago
How many different 55​-letter words can be made a. if the first letter must be Upper K or Upper XK or X and no letter may be​ re
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Answer:

(a) The number of 5-letter word that can be formed (without repetition) such that the first letter is K or X is 607,200.

(b) The number of 5-letter word that can be formed (with repetition) such that the first letter is K or X is 913,952.

(c) The number of 5-letter word that can be formed (without repetition) such that the first letter is K or X and the last is J is 24,288.

Explanation:

In this case we need to form a 5 letter word.

(a)

The condition applied is: 1st letter is K or X.

The word will of the form: K _ _ _ _ or X _ _ _ _

There are 2 ways to fill the first space, i.e. with either K or X.

Repetition is not allowed.

The remaining 4 spaces can be filled in (25 × 24 × 23 × 22) ways.

Then the total number of 5-letter word that can be formed (without repetition) such that the first letter is K or X is:

Number of 5-letter word = 2 × 25 × 24 × 23 × 22 = 607200

Thus, the number of 5-letter word that can be formed (without repetition) such that the first letter is K or X is 607,200.

(b)

In case the repetition are allowed the number of 5-letter word that can be formed (without repetition) such that the first letter is K or X is:

Number of 5-letter word = 2 × 26 × 26 × 26 × 26 = 913952

Thus, the number of 5-letter word that can be formed (with repetition) such that the first letter is K or X is 913,952.

(c)

The condition applied is: 1st letter is K or X and the last letter is J.

The word will of the form: K _ _ _ J or X _ _ _ J

There are 2 ways to fill the first space, i.e. with either K or X, and the last with J.

Repetition is not allowed.

The remaining 3 spaces can be filled in (24 × 23 × 22) ways.

Then the total number of 5-letter word that can be formed (without repetition) such that the first letter is K or X and the last is J is:

Number of 5-letter word = 2 × 24 × 23 × 22 = 24288

Thus, the number of 5-letter word that can be formed (without repetition) such that the first letter is K or X and the last is J is 24,288.

3 0
3 years ago
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