Question

Can someone please help me with this?!

Answer 1

Answer:

26) Let the first number be x.

Sum of three consecutive even numbers:

$x+(x+2)+(x+4)=-84$

$x+x+2+x+4=-84$

$3x+6=-84$

Subtract 6 from both sides:

$3x+6-6=-84-6$

$3x=-90$

Divide both sides by 3:

$\frac{3x}{3}=\frac{-90}{3}$

$x=-30$

To find the other two numbers, add 2 and 4 respectively:

$(-30+2=-28)(-30+4=-26)$

27) Let the first number be x.

Sum of three consecutive odd integers:

$x+(x+2)+(x+4)=141$

$3x+6=141$

Subtract 6 from both sides:

$3x+6-6=141-6\\3x=135$

Divide both sides by 3:

$\frac{3x}{3}=\frac{135}{3}\\x=45$

To find the other two numbers, add 2 and 4 respectively:

$(45+2=47)(45+4=49)$

28) Let the first number be x.

Sum of four consecutive integers:

$x+(x+1)+(x+2)+(x+3)=54$

$4x+6=54$

Subtract 6 from both sides:

$4x+6-6=54-6\\4x=48$

Divide both sides by 4:

$\frac{4x}{4}=\frac{48}{4}\\x=12$

To find the other three numbers, add 1, 2 and 3 respectively:

$(12+1=13)(12+2=14)(12+3=15)$

29) Let the first number be x.

Sum of four consecutive integers:

$x+(x+1)+(x+2)+(x+3)=-142$

$4x+6=-142$

Subtract 6 from both sides:

$4x+6-6=-142-6$

$4x=-148$

Divide both sides by 4:

$\frac{4x}{4}=\frac{-148}{4}\\x=-37$

To find the other three numbers, add 1, 2 and 3 respectively:

$(-37+1=-36)(-37+2=-35)(-37+3=-34)$