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natita [175]
3 years ago
5

Pls help ASAP thank u

Mathematics
1 answer:
MaRussiya [10]3 years ago
4 0

Answer:

20 visits

Step-by-step explanation:

20 is the least common multiple of 4 and 10.

Multiples of 4:

4, 8, 12, 16, 20, 24, 28...

Multiples of 10:

10, 20, 30, 40, 50, 60, 70

After 20 visits, you will receive the discount and a free hair product at the same time.

Hope this helps.

You might be interested in
If a ball is kicked with a speed of 2.5 m/s, how long does it take the ball to move 40 meters? (no units required for your answe
noname [10]

Answer:

16

Step-by-step explanation:

40 divided by 2.5 equals 16

4 0
3 years ago
Jason is cutting a roll of sausage into pieces that are 1/2 inches thifk if the roll is 6 inchew long how many pieces of sausage
e-lub [12.9K]

Answer:

12 rolls

Step-by-step explanation:

Jason wants to cut roll into pieces that are each 1/2 inches thick. 1/2 is equal to 0.5, so thickness of each roll is 0.5 inches

Total length of the roll is 6 inches. We have to find how many small 0.5 inch rolls can he cut.

In simple words we can say that we have to find: how many 0.5 inches can be out from 6 inches. This type of problem is solved by division. Dividing 6 inches by 0.5 inches will give us: How many 0.5 inches can be cut out from 6 inches i.e. how many 0.5 inches roll can be made from 6 inches roll

6 divided by 0.5 is 12.

This means Jason can cut 12 rolls of sausages each with thickness of 0.5 inches from a roll of 6 inches.

7 0
3 years ago
Please help I’m really stuck !!
lbvjy [14]

The number in the parenthesis is the X value and they are looking for what the Y value is at that specific X.

So when you look at f(-2), find the Y value where the line crosses.

At X-2, the line crosses Y at -2

At X = 2, the line crosses at Y = 2

At X = 4, the line crosses at Y = 1

The answer is -2,2,1

6 0
3 years ago
In this question, i is a unit vector due east and j is a unit vector due north. A cyclist rides at a speed of 4 m/s on a bearing
d1i1m1o1n [39]

<u>Answer:</u>

a) 1.04i + 3.86j

b) magnitude = 8; bearing = 302.7°

<u>Step-by-step explanation:</u>

a)

The  first diagram represents the velocity vector of the cyclist.

To express this vector in the form xi + yj, we have to find the components of the vector in the horizontal (i) and vertical (j) directions.

If we consider the horizontal component of the vector to be x, and the vertical component to be y, then:

• horizontal component ⇒ sin (15^{\circ}) = \frac{x}{4}

                                       ⇒ x = 4\space\ sin(15^{\circ})

                                       ⇒ x \approx \bf 1.04

• vertical component ⇒ cos(15^{\circ}) = \frac{y}{4}

                                   ⇒ y = 4 \space\ cos(15^{\circ})

                                   ⇒ y \approx \bf 3.86

Now that we have the values of both the horizontal and vertical component, we can write the vector in the form of xi + yj:

vector ⇒ 1.04i + 3.86j

b)

The second diagram shows the first vector (red), the second vector (blue), and the resultant vector <em>v</em> (black). The dashed lines represent the components of the respective vectors.

To add two vectors given their magnitudes and direction, we have to add their components.

In order to find the horizontal and vertical components of the given vectors, we can use a method similar to that used above, so that:

○ For the first vector (magnitude 6):

• horizontal component ⇒ x = 6 \space\ sin (60^{\circ})

                                       ⇒ \bf 5.2

• vertical component ⇒ y = 6 \space\ cos(60^{\circ})

                                   ⇒ y = \bf 3

○ For the second vector (magnitude 2):

• horizontal component ⇒ x = 2 \space\ cos (40^{\circ})

                                       ⇒ \bf 1.5

• vertical component ⇒ y = 2 \space\ sin(40^{\circ})

                                   ⇒ \bf 1.3

Now we can add the respective components together:

v = 5.2i + 3j  +  1.5i + 1.3j

 ⇒ (5.2 + 1.5)i + (3 + 1.3)j

 ⇒  6.7i + 4.3j

∴ Magnitude of v ⇒ |v| = \sqrt{(6.7)^2 + (4.3)^2}

                             ⇒ |v| \approx \bf 8

To find the bearing of <em>v</em>, we have to first calculate the angle marked \alpha:

tan \alpha = \frac{4.3}{6.7}

⇒ \alpha = tan^{-1}(\frac{4.3}{6.7})

⇒ \alpha = \bf 32.7^{\circ}

∴ Bearing = 270° + 32.7°

                = 302.7°

8 0
2 years ago
Due tonight Please help me 20 points!!
Gala2k [10]

Answer:

the table goes:

12 -> 7.50

13 ->8.0

15 -> 9.0

16 -> 9.5

Step-by-step explanation:

a) $15

b) 25 bagels

5 0
3 years ago
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