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Anuta_ua [19.1K]
3 years ago
9

What is the lenght of the hypotenuse 12mi 5mi c=​

Mathematics
1 answer:
Nadya [2.5K]3 years ago
8 0

{12}^{2}  \times  {5}^{2}  = 169

\sqrt{169}  = 13

Hypotenuse is 13 mi.

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If f(x)=x^2+2x-3 and g(x)=x^2-9, find (f/g)(4) and (f+g)(4)
Likurg_2 [28]

Answer:

<u>Part 1:</u> Find (f/g)(4) = 3

<u>Part 2:</u> Find (f+g)(4) = 28

Step-by-step explanation:

<u>Part 1:</u> Find (f/g)(4):

(f/g)(4) means <em>divide f function by g function and simplify it. Then plug in 4 into x of that simplified function.</em>

Let's do this:

\frac{x^2+2x-3}{x^2-9}\\=\frac{(x+3)(x-1)}{(x-3)(x+3)}\\=\frac{x-1}{x-3}

Plugging in 4 into x gives us:

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The answer is 3

<u></u>

<u>Part 2:</u> Find (f+g)(4):

(f+g)(4) <em>means add f function and g function and simplify it. Then plug in 4 into x of that simplified function.</em>

Let's do this:

(x^2+2x-3)+(x^2-9)\\=2x^2+2x-12

Plugging in 4 into x gives us:

2x^2+2x-12\\=2(4)^2+2(4)-12\\=28

The answer is 28

5 0
3 years ago
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Answer:

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Step-by-step explanation:

18: 12

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3 : 2

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8 0
3 years ago
Read 2 more answers
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6 0
3 years ago
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