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777dan777 [17]
3 years ago
5

Rewrite the equation 2x + 4y + 2 = 3y + 5 in general form. 

Mathematics
2 answers:
AleksAgata [21]3 years ago
5 0

The answer is B) 2x + y - 3 = 0

In order to get this, start with the original equation and then subtract the parts from the right side.

2x + 4y + 2 = 3y + 5 ----> Subtract 3y from both sides

2x + y + 2 = 5 ----> subtract 5 from both sides

2x + y - 3 = 0

Anika [276]3 years ago
4 0

General form of any equation is of the form AX+BY+C=0

Here A,B,C are three real numbers

THe given equation is

2x +4y+2=3y+5

To make right side equal to 0 we subtract 3y and 5 both sides

2x+4y+2-3y-5=0

Simplifying like terms

2x+y-3=0

Option B is the right answer

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In the 2014 - 2015 school year, the mean score on the critical reading of the SAT was 490 with a standard deviation of 102 for j
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<u>Answer:</u>

The Ranking Percentile is (B) 97.5%

<u>Explanation :</u>

To find the percentile rank we need to find the z- score. After finding the z-score match this value with the corresponding value in z-score table.

Formula to find the z-score

Z-score=\frac{\text { scored obtained - mean }(\mu)}{\text { standard deviation }(\sigma)}

Substituting the values in the above equation, we find

Z-score= \frac{(694-490)}{102}=2

So, the Z-score is +2

Now, the corresponding value of Z-score 2 in the table is 0.9772

or the percentile score is 97.72 ~ 97.5 .

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Answer:

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Step-by-step explanation:

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Suppose the scores on an exam are normally distributed with a mean μ = 75 points, and standard deviation σ = 8 points.
Artyom0805 [142]

Answer:

P(X>69)=P(\frac{X-\mu}{\sigma}>\frac{69-\mu}{\sigma})=P(Z>\frac{69-75}{8})=P(Z>-0.75)

And we can find this probability on this way:

P(Z>-0.75)=1-P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problm

Let X the random variable that represent the scores on an exam of a population, and for this case we know the distribution for X is given by:

X \sim N(75,8)  

Where \mu=75 and \sigma=8

We are interested on this probability

P(X>69)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>69)=P(\frac{X-\mu}{\sigma}>\frac{69-\mu}{\sigma})=P(Z>\frac{69-75}{8})=P(Z>-0.75)

And we can find this probability on this way:

P(Z>-0.75)=1-P(Z

4 0
3 years ago
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