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rjkz [21]
3 years ago
12

Can somebody please answer this question correctly please

Mathematics
2 answers:
yan [13]3 years ago
8 0

Answer:

so I know the first answer

Step-by-step explanation:

so total is 40 points but the total is divide by 2 points so we get 20 questions so if u get 6 wrong then you get 20-6=14... therefore the score with 6 wrong is 14

Tema [17]3 years ago
4 0

Answer:

sorry i don't know the answer

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Find the range of the following piecewise function.
Olegator [25]

Answer:

  None of the Above

Step-by-step explanation:

The range is [2, ∞) excluding (2, 7) and [11, 16). No part of the piecewise function will give f(x) = 5, for example.

8 0
3 years ago
In which quadrant is the point (4,-2 located<br>​
zheka24 [161]

Answer:

quadrant 4

Step-by-step explanation:

Hope this helped :)

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4 0
3 years ago
Read 2 more answers
A. y= 1/2x-14<br> B. y=1/2x-5<br> C. y=2x-14<br> D. y=2x-5
DanielleElmas [232]

Answer:

B. y=1/2x-5

Step-by-step explanation:

From the graph, we read the slope of line JK.

slope = rise/run = -3/-6 = 1/2

The equation we need has the same slope.

y = mx + b

y = (1/2)x + b

It passes through point P(6, -2). Now we find b.

-2 = (1/2)(6) + b

-2 = 3 + b

b = -5

The equation is

y = (1/2)x - 5

6 0
2 years ago
PLEASE HELP I HAVE TEST!! Find the measure of the arc or angle indicated
I am Lyosha [343]

Answer:

Step-by-step explanation:

<JKL = 90 ( being inscribed angle in semi circle )

< JKP = 38 ( Inscribed angles on same arc are equal )

So now

<PKL = <JKL - < JKP

        = 90 - 38

        = 52

FINALLY

ARC PL = 2 * < PKL (Relation between arc and inscribed angle )

ARC PL = 2 * 52

             = 104

hope it helps :)

8 0
3 years ago
Polygon ABCD is a rectangle what is the area
Andre45 [30]

Solution:

As, You have Written Polygon ABCD is a rectangle.

It is a Four sided Polygon , having all it's interior angles equal to 90°.As well as Opposite sides are equal(AB=CD,AD=BC), equal diagonals(AC=B D).

Join any of the diagonal of Rectangle either AC or B D.

In Right Δ ABC , Right angled at B

{\text{Area (Right triangle ABC)}} =\frac{1}{2}\times AB \times BC---(1)

In Right  Δ ADC  , Right angled at D      

{\text{Area (Right triangle ABC)}} =\frac{1}{2}\times AD \times DC---(2)

Adding (1) and (2) that is LHS to LHS and RHS to RHS

Ar( Δ ABC) +Ar( Δ ADC)=\frac{1}{2}\times[ AB \times BC+ AD \times DC]\\\\=\frac{1}{2}[2 \times AB \times BC][\text{As, AB=CD, and BC=AD}]\\\\ = AB \times BC

So, Area of Rectangle= Product of any two Adjacent Sides

7 0
4 years ago
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