It would be 9 + x =16
To solve it, subtract 9 from both sides of the equal sign
So (9+x)-9=16-9
Which is x=7, so the answer is 7.
Neptune's distance from the sun is d₁ = 4.503 x 10⁹ km.
Mercury's distance from the sun is d₂ = 5.791 x 10⁷ km.
Calculate the number of times d₁ is greater than d₂.

Answer: 7.7759 x 10⁻¹ times
Answer:
The answer is B) 0.57.
Step-by-step explanation:
In this problem we have to apply queueing theory.
It is a single server queueing problem.
The arrival rate is
and the service rate is
.
The proportion of time that the server is busy is now as the "server utilization"and can be calculated as:

where c is the number of server (in this case, one server).
Total surface area is 152 cm
If you change the fraction to decimals that will make it easier to compare