Given the quadratic function g(x)=(x-2)^2+3, state the vertex of g(x)

Solve this equation and describe the steps you took.<br> 4( x + 7) = 38

Nikitich [7]

Answer:

x = 2.5

Step-by-step explanation:

4( x + 7) = 38

step 1 distribute the 4 to the x and 7

4 * x = 4x

4 * 7 = 28

we now have 4x + 28 = 38

step 2 subtract 28 from each side

28 - 28 cancels out

38 - 28 = 10

we now have 4x = 10

step 3 divide each side by 4

4x / 4 = x

10 / 4 = 2.5

we're left with x = 2.5

4 0

3 years ago

Read 2 more answers

1.)

VashaNatasha [74]

Answer:

1. z = -15

2. p = 7

3. h = -11

4. t = 14

5. q = 12

Step-by-step explanation:

1.

$\frac{z}{-5}+1=4$

Add -1 both sides,

$\frac{z}{-5}+1-1=4-1\\\frac{z}{-5}=3$

Multiply both sides by -5,

$\frac{z}{-5}\times-5=3\times-5\\z=-15$

2.

Distribute 3 in $p+2$ and then add -6p and -6 both sides.

$3(p+2)=6p-15\\3\times p+3\times2 = 6p-15\\3p+6=6p-15\\3p-6p=-15-6\\-3p=-21\\p=\frac{-21}{-3}=7$

3.

$\frac{h-7}{2}=3(h+8)$

Multiply both sides by 2,

$\frac{h-7}{2}\times2=3(h+8)\times2\\h-7=6(h+8)\\h-7=6h+48$

Add -6h and 7 both sides,

$h-6h-7+7=6h-6h+48+7\\-5h=55\\h=\frac{55}{-5}\\h=-11$

4.

$4t+2-5=3(t+7)-9\\4t-3=3t+21-9\\4t-3=3t+12$

Add -3t and 3 both sides.

$4t-3t-3+3=3t-3t+12+3\\t=15$

5.

$2(q-4)=4(q-8)\\2q-8=4q-32$

Add -2q and 8 both sides.

$2q-8-4q+8=4q-4q-32+8\\-2q=-24\\q=\frac{-24}{-2}\\q=12$

Therefore,

1. z = -15

2. p = 7

3. h = -11

4. t = 14

5. q = 12

4 0

4 years ago

Consider the line =−−8x6y1.

ICE Princess25 [194]

Answer:

Below

Step-by-step explanation:

Well I can't really see the equation but I can tell you how to do it.

Parallel slopes are the same slope as the equation.

For example, y = mx + b

The slope of a line parallel to it is m

Perpendicular slopes are the opposite reciprocal as the equation.

For example, y = mx + b

The slope of a line perpendicular to it is $-\frac{1}{m}$

6 0

3 years ago

Today, you earn a salary of $28,000. what will be your annual salary twelve years from now if you earn annual raises of 2.6 perc

Debora [2.8K]

Salary after 12 years = $28,000(1+0.026)^12 =$38100.12

8 0

3 years ago

Using Cramer’s Rule, what is the value of y in the system of linear equations below?

Vadim26 [7]

for the system of equations

$a_1x+b_1y=c_1 \\a_2x+b_2y=c_2$

the three matrices needed to use Cramer's Rule are:

$D=\left[\begin{array}{cc}a_1&b_1\\a_2&b_2\end{array}\right] \\\\D_x=\left[\begin{array}{cc}c_1&b_1\\c_2&b_2\end{array}\right] \\\\D_y=\left[\begin{array}{cc}a_1&c_1\\a_2&c_2\end{array}\right]$ .

To use Cramer's Rule we have to calculate the three determinants listed below of the matrices listed below.

$D=\left[\begin{array}{cc}2&5\\-3&-2\end{array}\right] \\\\D_x=\left[\begin{array}{cc}-13&5\\3&-2\end{array}\right] \\\\D_y=\left[\begin{array}{cc}2&-13\\-3&3\end{array}\right]$ .

The value of the determinants are shown below.

$det(D)=(2)(-2)-(-3)(5)=-4+15=11\\det(D_x)=(-13)(-2)-(3)(5)=26-15=11\\det(D_y)=(2)(3)-(-3)(-13)=6-39=-33\\$

The value of y is $\frac{det(D_y)}{det(D)}=-\frac{33}{11} =-3.$ .

3 0

4 years ago