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3 years ago

Para armar un prisma cuadrangular, Edgar trazó la plantilla y lo dividió en seis secciones, como se muestra en la imagen

Mathematics

1 answer:

Llana [10]3 years ago

4 0

Answer:

1. $x^{2} + x^{2} + (10\cdot x) \cdot (4)$

Step-by-step explanation:

(This exercise is written in Spanish and therefore explanation will be held in such language)

El área de este polígono regular es la suma de las áreas de los 4 rectángulos y 2 cuadrados, es decir:

$A_{tot} = 4\cdot A_{r} + 2 \cdot A_{c}$

$A_{tot} = 4 \cdot (10)\cdot x + 2\cdot x^{2}$

El cual corresponde con la opción 1.

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07.03 LC)

Inga [223]

$Q1.\\p\%=\dfrac{p}{100};\ 20\%=\dfrac{20}{100}=0.20=0.2\\\\20\%-French\ of\ 500\ people\\\\0.2\cdot500=100\leftarrow Answer$

$Q2.\\\dfrac{white}{all}\cdot\dfrac{yellow}{all-1}\\\\7+8+9=24-number\ of\ all\ roses\\\\\dfrac{9}{24}\cdot\dfrac{8}{24-1}=\dfrac{9}{24}\cdot\dfrac{8}{23}=\dfrac{72}{552}\leftarrow Answer$

$Q3.\\5-number\ of\ 2\\100-number\ of\ all\\\\\dfrac{5}{100}\leftarrow Answer$

$Q4.\\1+5+10=16-number\ of\ all\ marbles\\\\\dfrac{10}{16}\cdot\dfrac{10-1}{16-1}=\dfrac{10}{16}\cdot\dfrac{9}{15}\leftarrow Answer$

4 0

3 years ago

Read 2 more answers

You bought a large container of fruit punch. The label on the container says there are 128fluid ounces of fruit punch in the con

Alenkasestr [34]

Answer:

16 cups.

Step-by-step explanation:

We have been given that there are 128 fluid ounces of fruit punch in the container. We are asked to find the cups will be in 128 oz.

We know that 1 cup equals 8 fluid oz. To convert 128 oz into cups, we will divide 128 by 8.

$\text{Cups in 128 oz}=\frac{128\text{ oz}}{\frac{8\text{ oz}}{\text{1 cup}}}$

$\text{Cups in 128 oz}=\frac{128\text{ oz}}{8\text{ oz}}\times \text{1 cup}$

$\text{Cups in 128 oz}=16\times \text{1 cup}$

$\text{Cups in 128 oz}=16\text{ cups}$

Therefore, there are 16 cups in the container.

5 0

3 years ago

A pole that is 3 m tall casts a shadow that is 1.74 m long at the same time a nearby building casts a shadow that is 50.75 m lon

bija089 [108]

87.5

Tall. /. Shadow
3 / 1.74=. X /. 50.75
Cross multiply
152.25= 3x
Divide by 3
X= 87.5

4 0

3 years ago

What would be the sum of the lengths of the first and second diagonals rounded to the nearest whole number?

drek231 [11]

Answer:

16.17684994

Step-by-step explanation:

First diagonal

x^2 = a^2 + b^2

x^2 = 5^2 + 6^2

x^2 = 61

x ≈ 7.810249676

Second diagonal

x^2 = a^2 + b^2

x^2 = 7.810249676^2 + 3^2

x^2 = 70

x ≈ 8.366600265

Sum of both diagonals

8.366600265 + 7.810249676

= 16.17684994

6 0

3 years ago

How do i find the shorted distance between the point and the line

m_a_m_a [10]

Answer:

5 units

Step-by-step explanation:

3x + 4y = 8

4y = -3x+8

y = -3/4+2

The shortest distance between a point and a line is the perpendicular line.

Slope of the perpendicular line: 4/3 and point (-3,-2)

b = -2-(4/3)(-3) = 2

Equation of the perpendicular line: y=4/3x+2

y is equal y

4/3x+2= -3/4x+2

4/3x +3/4x = 2-2

x = 0

Plug x=0 into one of the equations to find y

y = 4/3(0) + 2

y = 2

(0,2) and (-3,-2)

Distance = sqrt [(-3-0)^2 + (-2-2)^2]

Sqrt (-3)^2+ (-4)^2

Sqrt 25 = 5

3 0

2 years ago