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IgorLugansk [536]
3 years ago
6

You roll a single die numbered from 1 to 6 twice. The probability of rolling an even number the first time and a 6 the second is

the setup. What is the probability "rolling an even number the first time"? (Answer in percentage)
Mathematics
1 answer:
Arlecino [84]3 years ago
7 0

Answer:

<h2>The answer is 50%</h2>

Step-by-step explanation:

step one :

first and foremost we are going to list the sample space related to a die

the same space is  S= {1,2,3,4,5,6}= 6

step two:

now the even numbers in the sample space are ={2,4,6}= 3

hence we can solve for the probability of obtaining an even number to be

Pr(even number)= 3/6= 1/2.

step three:

since we are to provide the answer in percentage format, we can easily do this by multiplying the answer by 100 to get the percentage

(1/2)*100= 0.5*100= 50%

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Brand 1    Brand 2    Difference

37734       35202        2532

45299      41635         3664

36240      35500        740

32100      31950         150

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\text{Sample Standard deviation, s} = \sqrt{\dfrac{(x-\bar{x})^2}{n-1}}

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=1441.21

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c)Calculate a 99% two-sided confidence interval on the difference in mean life.

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confidence interval = 939.5 \pm 3.499 \times \frac{1441.21}{\sqrt{8}} \right)

confidence interval = 939.5 - 3.499 \times \frac{1441.21}{\sqrt{8}} \right) to  = 939.5 + 3.499 \times \frac{1441.21}{\sqrt{8}} \right)

Confidence interval −843.396\ to  2722.396

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