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Colt1911 [192]
3 years ago
11

Using two or more complete sentences, describe how to find the general rule for the arithmetic sequence with a4 = -1 and a6 = -1

3. In your final answer, include all of your calculations.
Mathematics
1 answer:
adoni [48]3 years ago
5 0

Answer:

Step-by-step explanation:

to find the arithmetic sequence with a4=-1 and a6=-13

first: find the difference: an=a+(n-1)d

a4=-1

that means a1+d(4-1)=-1 ( since a4 given and need to find a1)

a1+3d=-1 first equation

a1+d(6-1)=-13 ( a6 is given)

a1+5d=-13 second equation

a1+3d=-1

a1+5d=-13 ( find a and d by subtraction)

a1+3d-a1-5d=-1-(-13)

2d=12

d=-12/2=-6 ( substitute d in the equation: a1+3d=-1)

difference =-6

a1=17

a1,a2,a3,a4,a5,a6,....

the sequence is : 17,11,5,-1,-7,-13,.....

hope it works

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Yuri [45]

Answer:

at the end of 1st year we pay $ 11756

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at the end of 4th year we pay $ 51427

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at the end of 6th year we pay $ 82001

Step-by-step explanation:

Given data

rate ( i ) = 6%

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no of time period ( n ) = 6

to find out

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solution

we know future payment formula i.e.

future payment = payment per period ( (1 + rate)^{n} - 1 )   / rate

put all these value and get payment per period

payment per period = future payment × rate  /  ( (1 + rate)^{n} - 1 )   / rate

payment per period = 82000 × 0.06  /  ( (1 + 0.06)^{6} - 1 )   / rate

payment per period = 82000 × 0.06 / 0.4185

payment per period = $ 11756.27

at the end of 1st year we pay $ 11756

and at the end of 2nd year we pay $ 11756 × ( 1  + 0.06) + 11756

and at the end of 2nd year we pay $ 24217

and at the end of 3rd year we pay $ 24217 × ( 1  + 0.06) + 11756

and at the end of 3rd year we pay $ 37426

and at the end of 4th year we pay $ 37426 × ( 1  + 0.06) + 11756

and at the end of 4th year we pay $ 51427

and at the end of 5th year we pay $ 51427 × ( 1  + 0.06) + 11756

and at the end of 5th year we pay $ 66269

and at the end of 6th year we pay $ 66269 × ( 1  + 0.06) + 11756

and at the end of 6th year we pay $ 82001

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Answer:

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Step-by-step explanation:

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