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levacccp [35]
3 years ago
7

Find the size of each of 6 payments made at the end of each year into a 6% rate sinking fund which produces $82000 at the end of

6 years. The payment size is $? rounded to the nearest cent
Mathematics
1 answer:
Yuri [45]3 years ago
4 0

Answer:

at the end of 1st year we pay $ 11756

at the end of 2nd year we pay $ 24217

at the end of 3rd year we pay $ 37426

at the end of 4th year we pay $ 51427

at the end of 5th year we pay $ 66269

at the end of 6th year we pay $ 82001

Step-by-step explanation:

Given data

rate ( i ) = 6%

Future payment  = $82000

no of time period ( n ) = 6

to find out

size of all of 6 payments

solution

we know future payment formula i.e.

future payment = payment per period ( (1 + rate)^{n} - 1 )   / rate

put all these value and get payment per period

payment per period = future payment × rate  /  ( (1 + rate)^{n} - 1 )   / rate

payment per period = 82000 × 0.06  /  ( (1 + 0.06)^{6} - 1 )   / rate

payment per period = 82000 × 0.06 / 0.4185

payment per period = $ 11756.27

at the end of 1st year we pay $ 11756

and at the end of 2nd year we pay $ 11756 × ( 1  + 0.06) + 11756

and at the end of 2nd year we pay $ 24217

and at the end of 3rd year we pay $ 24217 × ( 1  + 0.06) + 11756

and at the end of 3rd year we pay $ 37426

and at the end of 4th year we pay $ 37426 × ( 1  + 0.06) + 11756

and at the end of 4th year we pay $ 51427

and at the end of 5th year we pay $ 51427 × ( 1  + 0.06) + 11756

and at the end of 5th year we pay $ 66269

and at the end of 6th year we pay $ 66269 × ( 1  + 0.06) + 11756

and at the end of 6th year we pay $ 82001

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Answer:

C

Step-by-step explanation:

the numbers between 0.08 and 0.4 are:

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I bolded the number closest to your answer choices, hope this helps!

3 0
3 years ago
90° clockwise rotation<br> Help please
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Answer:

E' (-2,5)

F' (-3,1)

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Step-by-step explanation:

The rule for 90 degree clockwise rotation is (h,k) -> (k,-h). This means flip the x-value's sign and then switch x and y's position. For example E (-5,-2), first flip x's sign (5,-2) and then switch x and y's places (-2,5).

4 0
3 years ago
Triphasil-28 birth control tablets are taken sequentially, 1 tablet per day for 28 days, with the tablets containing the followi
bazaltina [42]

Answer:

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

Step-by-step explanation:

The total milligrams of levonorgestrel is:

L = L_{1} + L_{2} + L_{3}

In which L_{1}, L_{2} and L_{3} are the number of miligrams of levonorgestrel taken in each phase.

The total milligrams of ethinyl estradiol is:

E = E_{1} + E_{2} + E_{3}

In which E_{1},E_{2} and E_{3} are the number of miligrams of ethinyl estradiol taken in each phase.

We can solve this by phase.

Phase 1: 6 tablets, each containing 0.050 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

6*0.050mg = 0.30mg of levonorgestrel and 6*0.030mg = 0.18mg of ethinyl estradiol are taken.

So L_{1} = 0.30 and E_{1} = 0.18

Phase 2: 5 tablets, each containing 0.075 mg of levonorgestrel and 0.040 mg ethinyl estradiol

In this phase,

5*0.075mg = 0.375mg of levonorgestrel and 5*0.040mg = 0.20mg of ethinyl estradiol are taken.

So L_{2} = 0.375 and E_{2} = 0.20

Phase 3: 10 tablets, each containing 0.125 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

10*0.125mg = 1.25mg of levonorgestrel and 10*0.030mg = 0.30mg of ethinyl estradiol are taken.

So L_{3} = 1.25 and E_{3} = 0.30

The total milligrams of levonorgestrel is:

L = L_{1} + L_{2} + L_{3} = 0.30 + 0.375 + 1.25 = 1.925

The total milligrams of ethinyl estradiol is:

E = E_{1} + E_{2} + E_{3} = 0.18 + 0.20 + 0.30 = 0.68

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

6 0
3 years ago
If the factors of quadratic function g are (x − 7) and (x + 3), what are the zeros of function g?
MArishka [77]

Answer: B. -3 and 7

Step-by-step explanation:

To find the zeros, just move the constants to the other side,

x - 7 ⇒ x = 7

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Hope it helps!

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r-ruslan [8.4K]

Answer:

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Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

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The lower limit of this interval is:

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The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5405 + 1.96\sqrt{\frac{0.5405*0.4595}{185}} = 0.6123

The 95​% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).

3 0
3 years ago
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