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zloy xaker [14]
3 years ago
10

How many positive integers have one less digit than their squares?

Mathematics
1 answer:
kati45 [8]3 years ago
7 0

If we consider numbers of 1 or 2 digits the highest of these is 31, because 31^2 = 961 and 32^2 = 1024. So that gives us all integers between 4 and 31 inclusive. Total 28 integers.

No 3 digits number fits the bill so I think that is the answer

28 positive integers.

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