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Inessa [10]
3 years ago
5

2x + 75 = 8x + 9 Please help for a quiz

Mathematics
1 answer:
Archy [21]3 years ago
7 0

Answer: x=11

Step-by-step explanation:

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Which represents the solution(s) of the graphed system of equations, y = x2 + x – 2 and y = 2x – 2? (–2, 0) and (0, 1) (0, –2) a
Luda [366]

ANSWER

(0,-2), (1,0)

EXPLANATION

The first equation is

y =  {x}^{2}  + x - 2

The second equation is

y = 2x - 2

We equate both equations to get,

{x}^{2}  + x - 2 = 2x - 2

{x}^{2}  + x - 2x - 2 + 2 = 0

Simplify

{x}^{2}  - x = 0

Factor

x(x - 1) = 0

Either

x = 0

Or

x - 1 = 0

x = 1

Put x=0 or x=1 into the second equation to get,

y =   2(0) - 2 =  - 2

Or

y =   2(1) - 2 =  0

Therefore the solutions are;

(0,-2), (1,0)

3 0
3 years ago
Read 2 more answers
Find the circumference of the circle with 1/4 Pi square centimetre square 2<br>​
otez555 [7]

Answer:

The circumference of the circle is 6 cm (approximately).

Step-by-step explanation:

Given:

Area of the circle = 1/4π²

Now, to get the circumference of the circle we need the radius.

So, finding the radius by putting the formula of area:

Area = \pi r^{2}

\frac{1}{4} \pi ^{2} = \pi r^{2}

dividing π by both sides:

\frac{1}{4}\pi=r^{2}

using square root on both the sides:

\frac{1}{2}\sqrt{\pi } = r

So, the radius is \frac{1}{2}\sqrt{\pi }

Now, putting the formula of circumference:

circumference=2\pi r

                              =2\pi\frac{1}{2} \sqrt{\pi}

                              =\pi \sqrt{\pi}

putting the value of π =3.14

                              =3.14\times\sqrt{3.14}

                              =3.14\times1.77

                              =5.56

Circumference = 5.56 cm

Therefore, the circumference of the circle is 6 cm (approximately).

4 0
3 years ago
Does each function describe exponential growth or decay?
Aleksandr [31]
<h3>Answer: Only first two are exponential growth function and last three functions are exponential decay functions.</h3>

Step-by-step explanation: We need to describe exponential growth or decay for the given functions.

The standard exponential function equation is

y=a(b)^x.

Where a is the initial value and b is the growth factor.

Note: If value of b > 1, it would be an exponential growth and if b < 1, it would be an exponential decay.

Let us check them one by one.

y=(1.008^{1/12}})^{12t} => y=(1.008^})^{1/12\times{12t} }

=> y= (1.008)^t.

Value of b is 1.008 > 1, therefor it's an exponential growth function.

y=250(1+0.004)^t, also have b>1 therefor it's an exponential growth function.

All other functions has b values less than 1, therefore only first two are exponential growth function and last three functions are exponential decay functions.



5 0
3 years ago
What is the answer please
il63 [147K]

Answer:

submit search form of attract new you are doing well in the question

8 0
3 years ago
The figures below are similar.
jeyben [28]

Answer:

S=98

Step-by-step explanation:

If S2 is 196 we can divide that by two and get our answer: s=98

7 0
3 years ago
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