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3 years ago

15

Find three consecutive odd integers such that the sum of the smaller number and middle number is 27 less than 3 times the larges

t number. Please show how you did this.

1 answer:

Anna35 [415]3 years ago

4 0

$\bf \stackrel{\textit{smaller odd integer}}{2a+1}~\hspace{5em}\stackrel{\textit{middle odd integer}}{2a+3}~\hspace{5em}\stackrel{\textit{largest odd integer}}{2a+5}
\\\\[-0.35em]
\rule{34em}{0.25pt}$

$\bf \stackrel{\textit{sum of smaller and middle}}{(2a+1)+(2a+3)}~~\stackrel{is}{=}~~\stackrel{\textit{three times the largest, and less 27}}{3(2a+5)-27}
\\\\\\
4a+4=6a+15-27\implies 4a+4=6a-12\implies 12+4=6a-4a
\\\\\\
16=2a\implies \cfrac{16}{2}=a\implies 8=a
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
~\hfill \stackrel{2a+1}{17}~\hspace{7em}\stackrel{2a+3}{19}~\hspace{7em}\stackrel{2a+5}{21}~\hfill$

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3 years ago

9,16=7 <br> 4,36=8 <br> 121,81=20 <br> 25,49=?

Ilia_Sergeevich [38]

Answer:

12.

Step-by-step explanation:

We have been given format of different numbers. We are asked to find the missing value for our given format.

$9,16=7$

Taking square root of 9 and 16 we will get,

$\sqrt{9}=3$

$\sqrt{16}=4$

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Similarly, we can see that by taking the square root of all the on the left side of equation and adding them we get right side of equation.

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Upon taking square root of 25 and 49 we will get,

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4 years ago

Read 2 more answers

Please help and show all work thank you

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Sin(x) = Opp/hyp = $\sqrt{119}/12$
Cos(x)= adj/hyp = <span> $5/12$ </span>

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