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soldi70 [24.7K]
3 years ago
13

Solve 2x+4 so that it has no solution

Mathematics
1 answer:
Mrrafil [7]3 years ago
5 0
2x+4
/2. /2
X=2


I think that’s what your looking how to do
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Patrick drives his car at 120 km/h for 5 hours . how far did he go ?
Novay_Z [31]

Answer:

^speed, distance, and time^

my answer lies in paper

hope undertand

8 0
3 years ago
Tori bought 24 candy bars for 69 cents each. She used partial products to find the total cost in cents. Which are NOT possible p
forsale [732]

Answer:

Options A, B, C and D

Step-by-step explanation:

This question is not complete; here is the complete question.

Tori bought 24 candy bars for 69 cents each. She used partial products to find the total cost in cents. Which are NOT possible partial products for 24 × 69?

A. 24

B. 36

C. 180

D. 240

E. 1656

Cost of one candy = 69 cents  

Since, cost of 24 candies = Cost of one candy × Number of candies

                                          = 69 × 24

For partial product,

69 × 24 = (60 + 9)(20 + 4)

             = 60(20 + 4) + 9(20 + 4)

             = 60×20 + 60×4 + 9×20 + 9×4

             = 1200 + 240 + 180 + 36

             = 1656

Therefore, Options A, B, C and D are not possible partial products.

8 0
3 years ago
I need help with this!!
Strike441 [17]

Answer:

I think it's 64.95. double check it

7 0
3 years ago
Which combination of transformations can you use to show that one shape is congruent to another? A. dilations and reflections B.
lesya692 [45]

Question

Which combination of transformations can you use to show that one shape is congruent to another?

A. dilations and reflections

B. reflections and stretches

C. rotations and translations

D. reflections, dilations, and translations

E. rotations, translations, and dilationsANSWER -


ANSWER -

The correct answer to this is:

ROTATIONS AND TRANSLATIONS


Reflection and rotation can also be used but since their both grouped with dilations, they can't be used. When dilation is used, the size of the shape is changed and congruence won't be possible anymore . That's why the answer is the first option.




6 0
3 years ago
How would you solve this linear system?
Hoochie [10]

(x, y ) = (- 6, 3 )

Since both equations express y in terms of x, we can equate them

2x + 15 = - \frac{1}{3} x + 1

( add \frac{1}{3} x to both sides )

\frac{7}{3} x + 15 = 1 ( subtract 15 from both sides )

\frac{7}{3} x = - 14

( multiply both sides by 3 and divide by 7 )

x = ( 3 × - 14 )/7 = - 6

substitute x = - 6 into either of the 2 equations for y- coordinate )

y = ( 2 × - 6 ) + 15 = 3

solution : (x, y ) = ( - 6, 3 )


8 0
3 years ago
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