I'm in a really hard unit in science, genetics. I'm learning about the Punnett Square. How does it work? It's confusing!

1 answer:

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A Punnett Square is used to predict the chances of an offspring to have its parents' traits. These squares are most commonly divided into four parts, with each part equaling a 25% chance of the offspring receiving that set of genes.

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In the human brain, a great deal of synaptic pruning occurs in early childhood. This pruning appears to be:_______.

Alex

Answer: D. An adaptive process that allows children to deal more efficiently with their environment.

Explanation:

Synaptic pruning is a natural process between early childhood and adulthood which occurs in the brain. The brain removes the extra synapses during synaptic pruning. Synapses are brain structures that allow the neurons to transmit to another neuron an electrical or chemical signal.

Synaptic pruning is thought to help the brain transition from adolescence, when it can quickly learn and make new connections, to adulthood, when it is much more stable in its structure, but can concentrate on a single question for longer and conduct more complex thinking processes. Synaptic pruning make brain more adaptive to the external environment in early ages.

Hence, the correct option is D. An adaptive process that allows children to deal more efficiently with their environment.

4 0

3 years ago

Consider the following three populations of birds. Assume HW equilibrium. With these birds red coloring is recessive, while brow

bixtya [17]

Answer:

Red allele frequency will be highest in population II

Population III can undergo bottleneck effect

The frequency of the brown allele will least likely be altered in the population I

Explanation:

Population I -

Total population - $670$

Brown birds - $603$

Red birds - $67$

Population II

Total population - $100$

Brown birds - $90$

Red birds - $10$

Population III

Total population - $30$

Brown birds - $27$

Red birds - $3$

Frequency of red birds in population I

$\frac{67}{670} = 0.1$

Frequency of red birds in population II

$\frac{10}{90} = 0.11$

Frequency of red birds in population III

$\frac{3}{30} = 0.1$

Red allele frequency will be highest in population II and it will be equal to $\sqrt{0.11} = 0.33$ as compared to $0.31$ in case of population I and III