Remember
(x^m)/(x^n)=x^(m-n)
(q^(33/4))/(q^8)=q^((33/4)-8)
what is 33/4-8?
33/4-8=33/4-32/4=1/4
result is
q^1/4 or
![\sqrt[4]{q}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7Bq%7D%20)
answer is
36...................4×11=44 4×7=28 44+28=72 72÷2=36
Answer:
9ab/8
Step-by-step explanation:
-3/4 a * -3/2 b
negative time negative is positive
3*3/(4*2) ab
9ab/8
we can make the number a mixed number but it is not usually done
(1 1/8 ) * ab
Use the final digit to get the answer:
The final digit is 3, therefore the only two consecutive numbers that add and end in 3 is 6 and 7.
Using this logic, the only two numbers are 26 and 27
