-px+r=-8x-2 solve for x

Sixty percent of the customers who go to Sears Auto Center for tires buy four tires and 22% buy two tires. Moreover, 12% buy few

kozerog [31]

Answer:

A Cumulative probability distribution for the number of tires bought is prepared below.

Step-by-step explanation:

We are given that Sixty percent of the customers who go to Sears Auto Center for tires buy four tires and 22% buy two tires. Moreover, 12% buy fewer than two tires, with 6% buying none.

The cumulative probability distribution for the number of tires bought is given by;

No. of tires Probability Distribution Cumulative Probability

Distribution

0 6% 6%

1 6% 12%

2 22% 34%

3 6% 40%

4 60% 100%

Now, here we are given within the question about:

P(0 tires) = 6%

P(2 tires) = 22%

P(4 tires) = 60%

Also, P(Fewer than 2 tires) = 12% which means P(0 tires) + P(1 tire) must be equal to 12%. So, P(1 tire) = 12% - 6% = 6%.

And, in the end P(3 tires) = 100% - 6% - 6% - 22% - 60% = 6%.

3 0

3 years ago

If seven times a number is added to the squares of the number and the result is negative twelve, what are the numbers?

AleksAgata [21]

Let's name the number 'n'. Now write an equation. 7*n +n^2 =12Now you can form a quadratic. n^2 +7n-12=0. Now you can use a myriad of methods to solve it. If you still need help, just message me.

6 0

3 years ago

Which expression is equivalent to 7/32 + 2/32

Marta_Voda [28]

Answer:

36 square root 2 also known as C

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

5) In a certain supermarket, a sample of 60 customers who used a self-service checkout lane averaged 5.2 minutes of checkout tim

Ne4ueva [31]

Answer:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

$S_p=2.940$

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

$df=60+72-2=130$

$p_v =P(t_{130}$

Assuming a significance level of $\alpha=0.05$ we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

Step-by-step explanation:

Data given

Our notation on this case :

$n_1 =60$ represent the sample size for people who used a self service

$n_2 =72$ represent the sample size for people who used a cashier

$\bar X_1 =5.2$ represent the sample mean for people who used a self service

$\bar X_2 =6.1$ represent the sample mean people who used a cashier

$s_1=3.1$ represent the sample standard deviation for people who used a self service

$s_2=2.8$ represent the sample standard deviation for people who used a cashier

Assumptions

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

And t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

System of hypothesis

Null hypothesis: $\mu_1 \geq \mu_2$

Alternative hypothesis: $\mu_1 < \mu_2$

This system is equivalent to:

Null hypothesis: $\mu_1 - \mu_2 \geq 0$

Alternative hypothesis: $\mu_1 -\mu_2 < 0$

We can find the pooled variance:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

And the deviation would be just the square root of the variance:

$S_p=2.940$

The statistic is given by:

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

The degrees of freedom are given by:

$df=60+72-2=130$

And now we can calculate the p value with:

$p_v =P(t_{130}$

Assuming a significance level of $\alpha=0.05$ we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

5 0

3 years ago

PLZ HELP ME

NeTakaya

Answer:

see below

Step-by-step explanation:

The shading is below the line in both cases. The dashed line has negative slope, so the inequality associated with it is ...

y < -2x +4 . . . . . . note that the < symbol has no "or equal to"

The solid line has positive slope, so its inequality is ...

y ≤ 2x +4

Both these inequalities are found in choice B.

6 0

2 years ago