Find the greatest possible error for the measurement 53.9 feet.

Mathematics

1 answer:

deff fn [24]3 years ago

8 0

The greatest possible error is 0.5 feet

You might be interested in

isabel lives 3/4 mile from school, Janet lives 2/3 mile from school how much farther in miles does isabel live from school than

anyanavicka [17]

Hey There!

Steps to solve (steps will be in numerical order)

1. Find the lcd of the fractions $\frac{3}{4}$ and $\frac{2}{3}$ . The lcd for both problems will be 12.

2. To rewrite $\frac{3}{4}$ you have to multiply the numerator and denominator by three since the lcd is 12. So you're new fraction will be $\frac{9}{12}$ . For the second fraction, since the lcd is 12 you will multiply the numerator and denominator by 4. You're new fraction will be $\frac{8}{12}$ .

3. Since the problem contains the math keyword "Further", you automatically know you have to subtract, now subtract $\frac{9}{12}$ - $\frac{8}{12}$ . First, start of by subtracting the numerators, so subtract 9-8=1 , remember the denominators will always stay the same.

In conclusion, you're answer will be $\frac{1}{12}$ , so Isabel lives $\frac{1}{12}$ farther away from Janet.

Hope This Helps :)

3 0

3 years ago

Read 2 more answers

I will gib brainliest if u help me >:C

zzz [600]

Answer:

1,800

Step-by-step explanation:

Why is because 6 is over for and u estimate to the nearest hundredth and then again the six is still there so u estimate the with the 100 place with give u a 800 so its 1,800

6 0

3 years ago

What is 3√125x^12 A) 5x^2 B) 5x^4 C) 25x^2 D) 25x^4

Schach [20]

$\sqrt[3]{125x^{12}}=\sqrt[3]{125}\cdot\sqrt[3]{x^{4\cdot3}}=5\sqrt[3]{(x^4)^3}=5x^4\\\\\text{Answer:}\ B)\ 5x^4\\\\\text{Used:}\\\sqrt[n]{a\cdot b}=\sqrt[n]{a}\cdot\sqrt[n]{b}\\\\(a^n)^m=a^{n\cdot m}\\\\\sqrt[n]{a^n}=a$