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jenyasd209 [6]
3 years ago
13

Match the real-world problem to its constant of proportionality.

Mathematics
1 answer:
FrozenT [24]3 years ago
8 0

Real word problem ⇒ constant of proportionality

$4.16 for 4 pounds of bananas ⇒ 1.04

$16.48 for 8 pounds of potatoes  ⇒ 2.06

$18.36 for 2 pizzas  ⇒ 9.18

2 cups of flour to make 36 cookies ⇒ 18

<em><u>Solution:</u></em>

A proportional relationship is one in which two quantities vary directly with each other.

We say the variable y varies directly as x,

if for x ∝ y

then,  x = y k

Where "k" is called constant of proportionality

k = \frac{x}{y}

<em><u>$4.16 for 4 pounds of bananas</u></em>

x = 4.16 and y = 4

k = \frac{4.16}{4} = 1.04

Thus constant of proportionality is 1.04

<em><u>$16.48 for 8 pounds of potatoes</u></em>

x = 16.48 and y = 8

k = \frac{16.48}{8} = 2.06

Thus constant of proportionality is 2.06

<em><u>$18.36 for 2 pizzas</u></em>

x = 18.36 and y = 2

k = \frac{18.36}{2} = 9.18

Thus constant of proportionality is 9.18

<em><u>2 cups of flour to make 36 cookies</u></em>

x = 36 and y = 2

k = \frac{36}{2} = 18

Thus constant of proportionality is 18

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a pyramid whose altitude is 5ft weighs 800lbs. at what distance from its vertex must it be cut by a plane parallel to its base s
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A structure which has a square base and four triangular sides meeting at a point is called pyramid.

At distance of 3.97 feet from its vertex , pyramid is cut by plane  so that the two solids of equal weight will be formed.

<u>It is assumed that weight of pyramid is proportional to its volume.</u>

So,   w  = k V , where V is volume of original pyramid and v is volume of small pyramid and k is constant.

Let us consider that at h  distance,  pyramid is cut from its vertex. So a small pyramid is also formed.

Assume that base area of original pyramid is A and base of small pyramid is a.

Volume of original pyramid is,   V= \frac{1}{3}  *A* 5

So, weight of original pyramid,  W = k *(\frac{1}{3}  *A* 5) = 800

Volume of small pyramid is,  v = \frac{1}{3}* a* h

So, weight of small pyramid, w = k*(\frac{1}{3}* a* h)=400

<u>Since, base and height of small pyramid and original pyramid are in proportion.</u>

So,  \frac{a}{A}  = (\frac{h}{5}) ^{2}

       a = (\frac{h}{5} )^{2}A

Substituting value of a in  equation k*(\frac{1}{3}* a* h)=400

So, k*(\frac{1}{3}* \frac{h^{2} }{25}A * h)=400

       (k*\frac{1}{3}* A*5)*\frac{1}{5} *\frac{h^{2} }{25} * h)=400

Since, (k *\frac{1}{3}  *A* 5) = 800, substitute in above equation.

    So, 800*\frac{h^{3} }{125}=400\\\\h^{3}=\frac{125}{2}\\\\h=\sqrt[\frac{1}{3} ]{62.5}\\\\h=3.97 feet

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brainly.com/question/17950304

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