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PolarNik [594]
3 years ago
13

Rectangle A has side lengths measuring 4 inches and 9 inches. Rectangle B is similar to rectangle A but has side lengths three t

imes longer
than rectangle A.
What is the area of rectangle B?
O A. 12 square inches
OB. 36 square inches
O c. 78 square inches
O D. 108 square inches
O E. 324 square inches
Mathematics
1 answer:
Bess [88]3 years ago
8 0
The answer is c. 78 square inches.

- you take both 4 and 9, multiply them by 3 which would give you 12 and 27. then you add 27 twice and 12 twice, together and get 78.
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Does anyone know what the vertex is?
sveticcg [70]

Answer:

A vertex (or node) of a graph is one of the objects that are connected together. The connections between the vertices are called edges or links. A graph with 10 vertices (or nodes) and 11 edges (links). For more information about graph vertices, see the network introduction.

7 0
3 years ago
Analyze the diagram below and complete the instructions that follow. (7x - 3) (12x -7) Solve for x.
yarga [219]

Answer:

Step-by-step explanation:

(7x-3)(12x-7)

we are solving for x and we are multiplying.

we start with the x's 7x*12x=  84x

-3*-7=21

so now we have

84x+21=0

the 0 is a placer for answering the question

we minus 21 to both sides

84x=-21

now we divide

84/-21= -4

x=-4

6 0
2 years ago
What value of x makes the equation true?<br><br> a -3<br><br> b -1<br><br> c 3<br><br> d 1
Ivenika [448]

Answer:

-3

Step-by-step explanation:

cause positive = negative

the answer is = negative

3 0
3 years ago
Calculate the surface area of a hockey puck with a height of 1 in. and a diameter of 3 in
uysha [10]

Answer:

23.56

Step-by-step explanation:

2(\pi r^{2}) + 2\pirh

2(\pi 1.5^{2})+ 2\pi(1.5)(1)

23.56

6 0
3 years ago
A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an
Nataly [62]

Answer:

The distance between the walls is 70 m.

Step-by-step explanation:

Given: A source of laser light is at point A on the ground between two parallel walls BE and CD . The walls are perpendicular to the ground that is

BE ⊥ ED and CD ⊥ ED

AB is a ray of light which strikes the wall on the left at point B which is 30 meters above the ground. that is BE = 30 m

AC is a ray of light which strikes the wall on the right at point C. The length of AC = 80 meters.

The ray AB makes an angle of 45 degrees with the ground that is m∠BAE = 45°

The ray AC makes an angle of 60 degrees with the ground that is m∠CAD = 60°

As shown is figure attached below.

WE have to find the distance between the walls that is Length of ED

Length of ED = EA + AD

Consider the Δ AEB,

Using trigonometric ratio,

\tan\theta=\frac{perpendicular}{base}

Here \theta=45^{\circ} , perpendicular = 30 m  and base we can find.

thus,

\tan 45^{\circ}=\frac{30}{EA}

We know \tan 45^{\circ}=1

thus, EA =  30 m

Consider the Δ AEB,

Using trigonometric ratio,

\cos\theta=\frac{base}{hypotenuse}

Here \theta=60^{\circ} , hypotenuse = 80 m  and base we can find.

thus, \cos 60^{\circ}=\frac{base}{80}

We know, \cos 60^{\circ}=\frac{1}{2}

thus, Base = 40 m

AD = 40 m

Thus, the distance between the walls that is the length of ED = 30 + 40 = 70 m

4 0
3 years ago
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