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Stels [109]
3 years ago
13

What is the correct classification for each given angle?

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
6 0
The answer to the question

Nuetrik [128]3 years ago
4 0

The meaning of the options are:

  • Acute: an angle between 0 and 90 degrees;
  • Straight: and angle of 180 degrees;
  • Right: an angle of 90 degrees
  • Obtuse: an angle of more than 90 degrees

So, AFB is acute, because it's and angle of 48 degrees, between it's complementary to BFC and they for a right angle.

DFB is obtuse, because it's the right angle DFC plus the angle CFB

Finally, CFD is right (we can only deduce this by looking at the picture)

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(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2
Montano1993 [528]

Answer:

\dfrac{m^3}{16p^2q^2}

Step-by-step explanation:

Given:

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}

1.

m^{-1}=\dfrac{1}{m}

2.

q^0=1

3.

2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}

4.

(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}

5.

m^{-1}=\dfrac{1}{m}

6.

2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}

7.

\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}

8.

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

8 0
3 years ago
A rectangular, above-ground swimming
gregori [183]
The answer is A. 158 lbs
3 0
3 years ago
Which equation has the same solution as 2x^2+16x-10=0
dmitriy555 [2]
D
Divide the whole thing by 2
2(X^2+8x-5)
X^2+8x. =5
Half of 8 is 4 sq it so you add 16
X^2+8x+16= 5+16
(X+4)^2=21
8 0
2 years ago
Read 2 more answers
If point Q does not lie on the x-axis or the y-
Harman [31]
E. II or IV only because it will have different signs if point Q was in either of those quadrants
4 0
2 years ago
22+n=−12<br> pls help me im kinda confused
Ede4ka [16]

Answer:

-34

Step-by-step explanation:

22+n=-12

n=-12-22

n=-34

When you bring a positive constant to the other side of the equal sign it goes negative and vise versa. Then you combine like terms.

Please follow me!!!! Hope this helps!!! Have a wonderful day :)

3 0
2 years ago
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