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kirill115 [55]
3 years ago
12

-3(x-1) + 8(x-3) = 6x + 7 - 5x

Mathematics
2 answers:
Mama L [17]3 years ago
8 0

Answer:

x=7

Step-by-step explanation:

-3(x-1) + 8(x-3) = 6x + 7 - 5x

Distribute

-3x +3 +8x -24 = 6x +7 -5x

Combine like terms

5x -21 = x+7

Subtract x from each side

5x-x-21 = 7

4x -21 =7

Add 21 to each side

4x-21+21 = 7+21

4x = 28

4x/4 = 28/4

x=7

ivolga24 [154]3 years ago
3 0

Answer:

x=7

Step-by-step explanation:

-3(x-1)+8(x-3)=6x+7-5x

-3x+3+8x-24=6x+7-5x

5x-21=x+7

4x=28

x=7

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3(x - 2) + 48 = -3x
kow [346]

Answer: X=-7

Step-by-step explanation:

Using PEMDAS;

Step 1: Distribute the "3" in the part of the equation "3(x-2)"

3x - 6

Step 2: Consider the equation as a whole with the newly part of the equation from step 1, as it is a part of the equation

Therefore, re-written as,

3x - 6 + 48 = -3x

Step 3: Evaluate the re-written equation

Using basic mathematics skills, we can evaluate the following,

3x - 6 + 48 = -3x ➡ -6 + 48 = -6x ➡ 42 = -6x ➡ -7 = x

As shown, the answer is x=-7.

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What is the equation of the line that passes through the point (-1,7) and is parallel to the line y= -2x-1
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if we look at the equation y = -2x - 1, is already in slope-intercept form, therefore, \bf y=\stackrel{slope}{-2}x-1 has a slope of -2.


now, parallel lines have exactly equal slopes, therefore a parallel to that one above, will have also a slope of -2, so we're really looking for a line whose slope is -2 and runs through -1, 7.


\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{7})\qquad \qquad \qquad slope =  m\implies -2\\\\\\\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-7=-2[x-(-1)]\\\\\\y-7=-2(x+1)\implies y-7=-2x-2\implies y=-2x+5

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