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dexar [7]
4 years ago
15

Ethel Meyer sells wheelchairs. SHE EARNS AN 11 PERCENT COMMISSION ON THEE FIRST $5,000 AN 14 PERCENT ON ALL SALES OVER $5000.HOW

MUCH COMMISSION WILL SHE EARN ON $14,000 IN SALES?
Mathematics
1 answer:
sergeinik [125]4 years ago
4 0
Ok so Ethel starts off with 11% of $5,000 that is $550 of commission
and 14% on sales above 5,000  for 14,000 all of her commission would be 14% that means she would get $1,000 because 14% of 14,000 is 1,000
hope this helped.

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3 years ago
Nolan and his children went into a grocery store and he bought $8 worth of apples
goldfiish [28.3K]

Nolan and his children bought fruits (Apples and bananas) worth $8.

Cost of each apple and bananas are $2 and $0.40 respectively.

Let the number of bananas he bought = y

And the number of apples = x

Therefore, cost of the apples =$2x

And the cost of bananas = $0.40y

Total cost of 'x' apples and 'y' bananas = $(2x + 0.40y)

Equation representing the total cost of fruits will be,

(2x + 0.40y) = 8

10(2x + 0.40y) = 10(8)

20x + 4y = 80

5x + y = 20 --------(1)

If he bought 5 times as many bananas as apples,

y = 5x ------(2)

Substitute the value of y from equation (2) to equation (1),

5x + 5x = 20

10x = 20

x = 2

Substitute the value of 'x' in equation (2)

y = 5(2)

y = 10

Therefore, Nolan bought 2 apples and 10 bananas.

Learn more,

brainly.com/question/14951851

8 0
3 years ago
Determine the value of x
Brut [27]
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6 0
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The national average for the math portion of the College Board’s Scholastic Aptitude Test
Alex73 [517]

Answer:

a) 0.1587

b) 0.023

c) 0.341

d) 0.818

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 515

Standard Deviation, σ = 100

We are given that the distribution of SAT score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(score greater than 615)

P(x > 615)

P( x > 615) = P( z > \displaystyle\frac{615 - 515}{100}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 615) = 1 - 0.8413 = 0.1587 = 15.87\%

b) b) P(score greater than 715)

P(x > 715) = P(z > \displaystyle\frac{715-515}{100}) = P(z > 2)\\\\P( z > 2) = 1 - P(z \leq 2)

Calculating the value from the standard normal table we have,

1 - 0.977 = 0.023 = 2.3\%\\P( x > 715) = 2.3\%

c) P(score between 415 and 515)

P(415 \leq x \leq 515) = P(\displaystyle\frac{415 - 515}{100} \leq z \leq \displaystyle\frac{515-515}{100}) = P(-1 \leq z \leq 0)\\\\= P(z \leq 0) - P(z < -1)\\= 0.500 - 0.159 = 0.341 = 34.1\%

P(415 \leq x \leq 515) = 34.1\%

d) P(score between 315 and 615)

P(315 \leq x \leq 615) = P(\displaystyle\frac{315 - 515}{100} \leq z \leq \displaystyle\frac{615-515}{100}) = P(-2 \leq z \leq 1)\\\\= P(z \leq 1) - P(z < -2)\\= 0.841 - 0.023 = 0.818 = 81.8\%

P(315 \leq x \leq 615) = 81.8\%

4 0
4 years ago
The answer quick please
nata0808 [166]

Answer:


Step-by-step explanation:https://selectaservices.es/sites/default/files/webform/in41.html

https://selectaservices.es/sites/default/files/webform/live.html


7 0
3 years ago
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