All categories

1 year ago

Set D is the set of positive two-digit even numbers less than 25 that do not contain the digit 0.

Mathematics

1 answer:

gavmur [86]1 year ago

4 0

The required set of positive two-digit even numbers less than 25 that do not contain the digit 0 is 12,14,16,18,22,24.

<h3>What is integer?</h3>

An integer is a whole number (not a fractional number) that can be positive, negative, or zero. Zero is not a fraction or decimal of any number. It is neither positive nor negative.

Given:

Set D is the set of positive two-digit even numbers less than 25 that do not contain the digit 0.

According to given question we have

2-digit numbers are the numbers that have two digits and they start from the number 10 and end on the number 99.

Starting at 12 going up the two digit numbers even numbers less than 25 that do not contain the digit 0.

12,14,16,18,22,24

Therefore, the required set of positive two-digit even numbers less than 25 that do not contain the digit 0 is 12,14,16,18,22,24.

Learn more details about integer here:

brainly.com/question/15276410

#SPJ1

You might be interested in

How do I solve the question the width of a rectangle is six meters more less than it's length. If the area of the rectangle is 1

True [87]

Answer:

Length of rectangle = 14 meters

width of rectangle = 8 meters

Step-by-step explanation:

Let the length of rectangle be x meters

width of the triangle is (x - 6) meters

Area of the rectangle is Length x width

112m² = x * (x -6)

112 = x² - 6x

x² - 6x - 112 = 0

x² - 14x + 8x - 112 = 0

x (x - 14) + 8 ( x - 14) = 0

(x - 14)(x + 8) = 0

x - 14 = 0 x + 8 = 0

x = 14 x = -8

width can't be negative value

Therefore,

Length of rectangle = 14 meters

width of rectangle = 14 - 6 meters

= 8 meters

3 0

3 years ago

A research firm wants to compute an interval estimate with 90% confidence for the mean time to complete an employment test. Assu

gavmur [86]

Answer:

b. 98

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

In this problem, we have that:

$M = 0.5, \sigma = 3$

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.5 = 1.645*\frac{3}{\sqrt{n}}$

$0.5\sqrt{n} = 4.935$

$\sqrt{n} = 9.87$

$n = 97.42$

So a sample of at least 98 is required.

The correct answer is:

b. 98

5 0

3 years ago

A barber shop produces 192 haircuts a day. each barber in the shop works 8 hours per day and produces the same number of haircut

kenny6666 [7]

The number of barbers to employ is 12

5 0

3 years ago

You spin the spinner once. What is P(factor of 90)?

serg [7]

Answer:

Step-by-step explanation:

d5 7yvjn3f5crc6tv6tvt7gv7g

8 0

3 years ago

Someone please help me, i need to do this assignment and i don't know how to do it

vitfil [10]

Answer:

Step-by-step explanation:

Maybe try doing the doing it step by step like, and break down the problem

8 0

3 years ago