Which expression is equal to 2x^2+2x−40/4x^2−12x−16 ⋅ 3x^2−3/x^2−5x

Mathematics

1 answer:

Leokris [45]4 years ago

4 0

Answer:

3(x−1)(x+5)/(2x(x−5))

Step-by-step explanation:

In general simplifying something like this requires you factor the various polynomials to see what factors may cancel.

$\dfrac{2x^2+2x-40}{4x^2-12x-16}\cdot\dfrac{3x^2-3}{x^2-5x}=\dfrac{2(x-4)(x+5)\cdot 3(x-1)(x+1)}{4(x-4)(x+1)\cdot x(x-5)}\\\\=\dfrac{3(x-1)(x+5)}{2x(x-5)}$

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