All categories

3 years ago

The concept of market conduct includes such things as ____.

Business

1 answer:

lbvjy [14]3 years ago

3 0

The concept of market conduct includes such things like profit , loss and assest growth targets.

Explanation:

Market conduct is used in insurance industry to describe the problems that are related to the sale and distribution of insurance. It deals with the pricing and promotion strategies based on the players in the market related to their aim , objective and desicion making process.

Based on this concept all consumers are seen as potential customers with similar needs. They have proper regulations to check the customers are charged fair and reasonable insurance prices.

They will also ensure whether the consumers have access to beneficial and compliant insurance products.

You might be interested in

A local candidate running for office would very much like to have your vote. She promises that she will "make the country better

tia_tia [17]

Answer:

Something to exchange is missing

Explanation:

Marketing is the term which is defined as the procedure of interesting the potential customers as well as clients in the products and the services. The process of marketing involves the distributing, promoting, researching and selling the products and services.

So, in the process of marketing there is exchange process which take place among the client and the company.

In this case, the marketing will not happen or occur in this condition or situation as there is nothing to exchange or exchange is missing.

5 0

3 years ago

In a research experiment, Priya hears the following list of words:

Juli2301 [7.4K]

Answer:

orange

hope this answer may help you

5 0

3 years ago

Read 2 more answers

Assume there are currently five firms producing and selling fertilizer in the South American market. Also assume that the produc

Jobisdone [24]

Answer:

It is given that in an oligopolistic market, there are at first five firms. At the point when the quantity of fums diminishes to three, it implies that the all out yield will likewise decrease. It is on the grounds that, all the makers are delivering separated items. The inventory of merchandise won't increment in light of the fact that the makers would have expanded the creation before, if that was conceivable. Hence, the balance amount will fall and in view of decrease in amount, cost will increase.

Thus, equilibrium price will likely <u>increase</u> and the equilibrium quantity will likely <u>decrease.</u>

3 0

4 years ago

An oil refinery is located on the north bank of a straight river that is 3km wide. A pipeline is to be constructed from the refi

Mariulka [41]

Answer:

$6,598,076.21

Explanation:

<h2>THE KEY IS TO FIND OUT THE COST FUNCTION, the calculations are very easy!!!</h2><h2></h2><h3>In order to find the cost function, take a look at the drawing attached. </h3>

We can see the river (sort of) that is 3 km wide and the storage tanks on the other side of the river 8 km apart.

<h3 />

Laying pipes under (across) the river costs 1,000,000 the km & laying pipes over land costs 500,000 per km.

<h3 /><h3>So basically the cost function is 1,000,000 multiplied by something plus 500,000 multiplied by another something.</h3><h3 />

The distance across the river can be found by using Pythagoras Theorem. A side is 3 km the other is unknown, so we call it X. And it is equal to:

$\sqrt{3^{2} +x^{2}}=\\\sqrt{9 +x^{2}}$

And we multiply it by 1,000,000; the cost of laying pipe under the river, the we get:

$1000000\sqrt{9+x^{2}$

The distance over the land is (8-x), as we can see in the drawing. So we multiply it by its cost, 500,000. And we get 500,000(8-x).

So the cost function f(x) would be:

$f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)$

<h2>From here, we just have to differentiate and the derivative found must be equal to zero in order to minimize cost. </h2><h3>The value of x when the derivative is zero is plugged in the original function to get the cost.</h3><h3 /><h2>LET'S DO THIS</h2>

$f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(x)=1000000(9+x^{2})^{1/2}+4000000-500000x\\f'(x)=\frac{1}{2} 1000000(9+x^{2})^{-1/2}(2x)-500000\\\\f'(x)=\frac{1000000x}{\sqrt{9+x^2}} - 500000$

$f'(x)=\frac{1000000x}{\sqrt{9+x^2}} - 500000=0\\\frac{1000000x}{\sqrt{9+x^2}} = 500000\\\frac{2x}{\sqrt{9+x^2}} = 1\\2x={\sqrt{9+x^2}}\\4x^2=9+x^2\\3x^2=9\\x^2=3\\x=\sqrt{3} \\$

And we plug square root of 3 in the original cost function ad we get

$f(\sqrt{3} )=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(\sqrt{3})=1000000\sqrt{9+(\sqrt{3} )^{2}} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{9+3} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{12}+500000(6.27)\\f(\sqrt{3})=1000000(3.46)+500000(6.27)\\f(\sqrt{3})=3464101.62+3133974.60\\f(\sqrt{3})=6598076.21\\$

<h2>so the minimal cost is $6,598,076.21</h2><h2 /><h3 />

6 0

4 years ago

Straight-Line Depreciation Irons Delivery Inc. purchased a new delivery truck for $42,000 on January 1, 2019. The truck is expec

choli [55]

Answer:

Explanation:

The computation of the depreciation expense under straight-line method is shown below:

= (Original cost - residual value) ÷ (useful life)

= ($42,000 - $1,990) ÷ (5 years)

= ($40,010) ÷ (5 years)

= $8,002

In this method, the depreciation is same for all the remaining useful life

The journal entries are shown below:

For 2019

Depreciation expense A/c Dr $8,002

To Accumulated Depreciation A/c $8,002

(Being depreciation expense is recorded)

For 2020

Depreciation expense A/c Dr $8,002

To Accumulated Depreciation A/c $8,002

(Being depreciation expense is recorded)

5 0

3 years ago