Given:
μ = 68 in, population mean
σ = 3 in, population standard deviation
Calculate z-scores for the following random variable and determine their probabilities from standard tables.
x = 72 in:
z = (x-μ)/σ = (72-68)/3 = 1.333
P(x) = 0.9088
x = 64 in:
z = (64 -38)/3 = -1.333
P(x) = 0.0912
x = 65 in
z = (65 - 68)/3 = -1
P(x) = 0.1587
x = 71:
z = (71-68)/3 = 1
P(x) = 0.8413
Part (a)
For x > 72 in, obtain
300 - 300*0.9088 = 27.36
Answer: 27
Part (b)
For x ≤ 64 in, obtain
300*0.0912 = 27.36
Answer: 27
Part (c)
For 65 ≤ x ≤ 71, obtain
300*(0.8413 - 0.1587) = 204.78
Answer: 204
Part (d)
For x = 68 in, obtain
z = 0
P(x) = 0.5
The number of students is
300*0.5 = 150
Answer: 150
Answer:
x^3+6x^2+11x+12
Step-by-step explanation:
(x+4)(x^2+2x+3)
=x(x^2+2x+3)+4(x^2+2x+3) [by multiplying with bith sides]
=x^3+2x^2+3x+4x^2+8x+12
=x^3+2x^2+4x^2+3x+8x+12
=x^3+6x^2+11x+12
(please mark me brainliest)
Answer:
the answer is (C) 2(1-2x)=x-3
Answer:
A and C
Step-by-step explanation:
i chose these bc they arwe the 2 reasonable ones
