The angle of elevation is = 70° and the distance the airplane travelled in the air is = 17,557ft
<h3>Calculation of the distance travelled</h3>
- To calculate the angle of elevation of the airplane
tan x° = opposite/adjacent
where opposite = 16,500 feet
adjacent = 6,000 ft
tan x° = 16,500 / 6,000
tan x° = 2.75
X = arctan ( 2.75)
X = 70°
- To calculate the distance the airplane travelled in the air Pythagorean Theorem is used.
C² = a² + b²
C² = 16,500² + 6,000²
C² = 272250000 + 36000000
C² = 308250000
C= √308250000
C= 17,557ft
Learn more about Pythagorean Theorem here:
brainly.com/question/343682
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The equation of a line is written as t = ax + b where a is the slope and b is the y-intercept.
Using the slope and y intercept given the equation is:
Y = 3x + 2
A = 1/2(8+4)(3)
A = 6 * 3
A = 18
answer
<span>18 square yards</span>
The answer is 43.6 your welcome 87.20 divided by two is 43.6.
Answer:
A) -2
Step-by-step explanation: