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3 years ago

Find the measure of an exterior angle of each regular polygon: 100-gon.

1 answer:

4 0

If this is a 100-gon, then not only does it have 100 sides, it also has 100 central angles. Each one measures 360/100 = 3.6. This is the vertex angle for each of those 100 triangles. 180 - 3.6 = 176.4, which has to be split equally between the 2 base angles. This puts each of those at 88.2. If you are looking for the exterior angle to each of those, it's the supplement of them. 180-88.2 = 91.8

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How can you solve for x and y?

galina1969 [7]

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7 0

3 years ago

Life Expectancies In a study of the life expectancy of people in a certain geographic region, the mean age at death was years an

Sphinxa [80]

Answer:

The probability that the mean life expectancy of the sample is less than X years is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is the mean life expectancy, $\sigma$ is the standard deviation and n is the size of the sample.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

We have:

Mean $\mu$ , standard deviation $\sigma$ .

Sample of size n:

This means that the z-score is now, by the Central Limit Theorem:

$Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

Find the probability that the mean life expectancy will be less than years.

8 0

2 years ago

I need help it is due on friday it is pythagorean theram please help

Mamont248 [21]

Sorry i don’t know if it’s me but i can’t see the picture.

4 0

3 years ago

Math question answer a b and c hurry answer each one

liraira [26]

A. let the distance be d
so we have Δd/Δt=8.8min
Δd= 8.8Δt
d=∫8.8Δt-------(1)

b. d should be positive because the diver is ascending at a positive rate relative to depth

c. d=rt
t=d/r = 32.12/8.8 min
t= 3.65min

3 0

3 years ago

Read 2 more answers

In December 2004, a report based on the National Survey on Drug Use and Health estimated that 20% of all Americans aged 16 to 20

o-na [289]

Answer:

542

Step-by-step explanation:

We are required to find the sample size at 98% confidence interval in this question

E = 0.04

P* = 20% = 0.20

n = p* x (1-p)(Zα/2÷E)²

α = 1 - 0.98

= 0.02

To get Critical value

= 0.02/2 = 0.01

The critical value at 0.01 is 2.33

Inserting values into formula:

O.2 x 0.8(2.33/0.04)²

= 0.8 x 0.2 x 58.25²

= 542.89

The value of n must be an integer therefore the answer is 542.

4 0

3 years ago