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3 years ago

Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest

Mathematics

2 answers:

Alina [70]3 years ago

3 0

Answer:

Step-by-step explanation:

Ainat [17]3 years ago

3 0

Answer:

26 participants

Step-by-step explanation:

At least 1 means one or more

1: 10 participants

2: 7 participants

3: 5 participants

4: 4 participants

total = 10+7+5+4 =26 participants

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Find the output, f, when the input, t, is 7.<br> f = 2t - 3f=2t−3

ella [17]

Answer:

f = 3 1/2

Step-by-step explanation:

f = 2t - 3f Substitute 7 for t

f = 2(7) - 3f Multiply

f = 14 - 3f

+3f + 3f Add 3f to both sides

4f = 14 Divide both sides by 4

f = 3 1/2

If this answer is correct, please make me Brainliest!

6 0

3 years ago

Okay, help me out here!!

luda_lava [24]

Answer:

65.8

Step-by-step explanation:

(2.6*4.7)/2=6.11

11*4.7=51.7

(4.7(17-(2.6+11)))/2=7.99

6.11+51.7+7.99=65.8

3 0

4 years ago

NO LINKS!!! Part 2: Find the Lateral Area, Total Surface Area, and Volume. Round your answer to two decimal places.

slava [35]

Answer:

<h3><u>Question 7</u></h3>

<u>Lateral Surface Area</u>

The bases of a triangular prism are the triangles.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the triangles (bases).

$\implies \sf L.A.=2(10 \times 6)+(3 \times 6)=138\:\:m^2$

<u>Total Surface Area</u>

Area of the isosceles triangle:

$\implies \sf A=\dfrac{1}{2}\times base \times height=\dfrac{1}{2}\cdot3 \cdot \sqrt{10^2-1.5^2}=\dfrac{3\sqrt{391}}{4}\:m^2$

Total surface area:

$\implies \sf T.A.=2\:bases+L.A.=2\left(\dfrac{3\sqrt{391}}{4}\right)+138=167.66\:\:m^2\:(2\:d.p.)$

<u>Volume</u>

$\sf \implies Vol.=area\:of\:base \times height=\left(\dfrac{3\sqrt{391}}{4}\right) \times 6=88.98\:\:m^3\:(2\:d.p.)$

<h3><u>Question 8</u></h3>

<u>Lateral Surface Area</u>

The bases of a hexagonal prism are the pentagons.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the pentagons (bases).

$\implies \sf L.A.=5(5 \times 6)=150\:\:cm^2$

<u>Total Surface Area</u>

Area of a pentagon:

$\sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}a^2$

where a is the side length.

Therefore:

$\implies \sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}\cdot 5^2=43.01\:\:cm^2\:(2\:d.p.)$

Total surface area:

$\sf \implies T.A.=2\:bases+L.A.=2(43.01)+150=236.02\:\:cm^2\:(2\:d.p.)$

<u>Volume</u>

$\sf \implies Vol.=area\:of\:base \times height=43.011193... \times 6=258.07\:\:cm^3\:(2\:d.p.)$

8 0

2 years ago

What's the measure of ABD, DBK, and KBC? Show all work.

Andrew [12]

Answer:

56.6

Step-by-step explanation:

Since BK is a bisector of ABC at B,

this implies that:

ABC = ABK + KBC

ABC = 28.3 + 28.3

ABC= 56.6

5 0

3 years ago

The measure of each interior angle of a regular polygon is 150 how many sides does the polygon have?

Dmitry [639]

The exterior and an interior angles always add up to 180 degrees.
180-150=One exterior angle
180-150=30
We know that all of the exterior angles add up to 360
360/30= the number of sides
360/30=12
The shape has 12 sides.

3 0

3 years ago